User:Allison K. Alix/Notebook/CHEM-581/2012/11/02

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Objective

  • Cross-link porphyrin/gluteraldehyde containing film
  • Take IR spectra of all films synthesized thus far

Description

  • A 6 molal solution of NaCl was prepared (see calculations in "Data"). This solution was heated to 70°C at which point a film containing 1mL porphyrin and 1mL gluteraldehyde was added. The film was left to stir in solution until a visible color change occured, at which point we could assume the crosslinking was complete.
  • IR spectral data was gathered for all films synthesized thus far. These spectra will later be analyzed to observe any apparent changes shifts in peaks due to the composition of the film

Data

Preparation of 6m NaCl
  • Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://api.formulasearchengine.com/v1/":): {\displaystyle molality = \frac {mol solute}{kg solvent} }


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://api.formulasearchengine.com/v1/":): {\displaystyle \frac {6 moles NaCl}{1 kg water} \times \frac {57.54 g NaCl}{moles NaCl} = \frac {345.24g NaCl}{1 kg water}}


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://api.formulasearchengine.com/v1/":): {\displaystyle 1 kg water \times \frac {1000 g water} {1 kg water} \times \frac {1 mL water} {1 g water} = 1000 mL water}


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://api.formulasearchengine.com/v1/":): {\displaystyle \frac {345.24g NaCl}{1 kg water} \times \frac {1 kg water} {1000 mL water} = \frac {34.524 g NaCl} {100 mL water}}

Notes

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