User:Helen L. Slucher/Notebook/CHEM 571/2013/10/09

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We are running the same procedure as yesterday only with an inhibitor, EHNA.


  • Screen shot 2013-10-29 at 4.18.11 PM.png


EHNA stock

  1. 5mg EHNA in 1mL DMSO ---> 15.9mM EHNA
  2. (1.9μL)(15.9mM EHNA)=(10mL)(C2). C2 ---> 3μM EHNA

The reaction samples will contain roughly 1nM EHNA