# BME100 s2015:Group4 9amL2

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# OUR TEAM

 Name: Measho Habtemichael Name: Aaron Frisby Name: Alexandra Torres Name: Your name Name: Amanda Nguyen

# LAB 2 WRITE-UP

## Descriptive Statistics

Experiment 1 - Human Study

0mg LPS Dose
Mean: 3.834 pg/mL
Standard Deviation: 1.523010177
Standard Error: 0.481618106

5mg LPS Dose
Mean: 8.932 pg/mL
Standard Deviation:1.593931547 pg/mL
Standard Error: 0.504045412 pg/mL

10mg LPS Dose
Mean: 61.622 pg/mL
Standard Deviation: 30.11069386 pg/mL
Standard Error: 9.521837451 pg/mL

15mg LPS Dose
Mean: 657.941 pg/mL
Standard Deviation: 212.9429762 pg/mL
Standard Error: 67.33848166 pg/mL

Experiment 2 - Rat Study

0mg LPS Dose
Mean:10.516 pg/mL
Standard Deviation: 2.225551617 pg/mL
Standard Error: 0.995296941 pg/mL

10mg LPS Dose
Mean:11.112 pg/mL
Standard Deviation:7.40288592 pg/mL
Standard Error: 3.31067123 pg/mL

## Results

Experiment 1- Human Study

Experiment 2 - Rat Study

## Analysis

Experiment 1 - Human Study

For the human study, an ANOVA test will be done, because we are trying to determine whether there is a significant difference between more than two groups of data. The human study contains four groups of data based on dosage.

According to the ANOVA, the p-value is 3.39728E-14, which is less than the given alpha value of .05, which means there is a statistically significant difference between the treatments. Because it is less than the alpha, individual comparisons must be done in order to determine if there is a significant difference between each of the dosages.

In order to determine if there is a significant difference between each of the tests, we conducted individual comparisons. A Bonferroni correction must be done because there are a total of six post-hoc tests. The alpha of .05 must be divided by 6 because there are six comparisons done in the test.

According to the data from the individual t-tests, each of the tests resulted in a p-value less than the Bonferroni correction, so the results of each dosage are significantly different.

Experiment 2 - Human Study

After running the T.Test the t-value came out to be 0.867403497. The ideal p-value is 0.05, whereas the t-value was relatively higher which indicated that the data collected is not significant. There is no other comparisons that are necessary for the values. Going back to the rat study, there is no real difference between the 0mg test and the 10mg test.

## Summary/Discussion

In the first experiment involving the human study, an ANOVA was done in order to determine whether there was a significant difference between the levels of Inflammotin protein found in individuals given different dosages of LPT. According to the ANOVA, the p-value was less than the alpha of 0.05, meaning that there was a significant difference each of the dosage groups. Then, t-tests was done with Bonferroni corrections was done in order to determine which groups were significantly different. According to the Bonferroni correction, the alpha value was changed to .05/6, because six different groups were being compared. After each of the t-tests were completed, all of t-test values were less than the corrected p-values, suggesting that there is a significant difference between all of the groups. Each dosage had a different effect on the levels of inflammatin.

In the second experiment, the effect of LPS on level of Inflammatin was examined in rats. A t-test was conducted on rats because there are only two groups being compared, one group given a 0 mg dosage and another group given a 10 mg dosage. According the the t-test, the determined value was 0.867403497, greater than the given alpha value of 0.05. This means that there is no significant difference between the dosages given to the rats and their levels of Inflammatin protein.

In comparing the two data sets, it can be seen that there is a significance in levels of Inflammatin in the human study rather than the rat study. For future experiments, tests involving LPT and it's effect on levels of inflammatin should be done on humans so that significant differences can be detected.