User:Allison K. Alix/Notebook/CHEM-581/2012/10/24: Difference between revisions
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==Objective== | ==Objective== | ||
* Take UV-Vis of porphyrin solutions | |||
* Re-do crosslinking of porphyrin films | |||
* Prepare sulfate solutions | |||
==Description== | ==Description== | ||
#UV-Vis Spectra of ''porphyrin solutions'' with the following concentrations were collected: | |||
## 25μM | |||
## 12.5μM | |||
## 6.75μM | |||
## 3.375μM | |||
## 1.6875μM | |||
# 10 mL 50 μM of the following ''sulfate solutions'' were prepared: | |||
## Na<sub>2</sub>SO<sub>4</sub> | |||
## Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> | |||
## Al<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> | |||
==Data== | ==Data== | ||
<div class="center" style="width:auto; margin-left:auto; margin-right:auto;">Preparation of 50 μM Na<sub>2</sub>SO<sub>4</sub></div> | |||
<math> \frac {142.07 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1 L} {1000mL} \times 10mL = 0.071035 g</math> | |||
0.071035 g Na<sub>2</sub>SO<sub>4</sub> in 10mL H<sub>2</sub>O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H<sub>2</sub>O. | |||
---- | |||
<div class="center" style="width:auto; margin-left:auto; margin-right:auto;">Preparation of 50 μM 72 wt% Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub></div> | |||
<math> \frac {72} {100} \times \frac {399.88 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1L} {1000mL} \times \frac 10mL = 0.144g </math> | |||
0.144 g 72 wt% Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> in 10mL H<sub>2</sub>O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H<sub>2</sub>O. | |||
---- | |||
<div class="center" style="width:auto; margin-left:auto; margin-right:auto;">Preparation of 50 μM Al<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub></div> | |||
<math> \frac {656.33 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1L} {1000mL} \times 10mL = 0.328g </math> | |||
0.328 g Al<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> in 10mL H<sub>2</sub>O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H<sub>2</sub>O. | |||
---- | |||
[[Image:GraphPorphyrinSolutions.png]] | |||
==Notes== | ==Notes== |
Revision as of 14:14, 6 November 2012
Experimental Chemistry | <html><img src="/images/9/94/Report.png" border="0" /></html> Main project page <html><img src="/images/c/c3/Resultset_previous.png" border="0" /></html>Previous entry<html> </html>Next entry<html><img src="/images/5/5c/Resultset_next.png" border="0" /></html> |
Objective
Description
DataPreparation of 50 μM Na2SO4
[math]\displaystyle{ \frac {142.07 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1 L} {1000mL} \times 10mL = 0.071035 g }[/math] 0.071035 g Na2SO4 in 10mL H2O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H2O. Preparation of 50 μM 72 wt% Fe2(SO4)3
[math]\displaystyle{ \frac {72} {100} \times \frac {399.88 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1L} {1000mL} \times \frac 10mL = 0.144g }[/math] 0.144 g 72 wt% Fe2(SO4)3 in 10mL H2O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H2O. Preparation of 50 μM Al2(SO4)3
[math]\displaystyle{ \frac {656.33 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1L} {1000mL} \times 10mL = 0.328g }[/math] 0.328 g Al2(SO4)3 in 10mL H2O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H2O.
NotesThis area is for any observations or conclusions that you would like to note.
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