# User:Garrett E. McMath/Notebook/Junior Lab/2008/09/15

E/M Ratio Lab Main project page
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# Lab 2: The Ratio e/m for Electrons

Notes By: Garrett McMath and Paul Klimov

SJK 00:22, 4 October 2008 (EDT)
00:22, 4 October 2008 (EDT)
Your raw data notebook is very good, reflecting the very good work you did in class. As I mention below, make sure to take a look at Paul's notebook for more feedback.

## Purpose and Objectives

The purpose of this laboratory is to measure the e/m ratio of electrons. This will be done by accelerating electrons into a strong magnetic field, which will cause the electrons to rotate in a circle on a plane perpendicular to the field.

## Theory

The Lorentz force, in the absence of an Electric field gives us:

$\displaystyle \vec{F}=e(\vec{v} \times \vec{B}) = m \frac{\vec{v}^{2}}{R}$

this implies:

$\displaystyle \frac{e}{m}=\frac{|\vec{v}|}{R|\vec{B}|}$

The electrons are accelerated through a potential V, implying:

$\displaystyle \frac{1}{2}mv^{2}=eV$

$\displaystyle v=\sqrt{\frac{2eV}{m}}$

Now, we use this velocity in the above equation for the ratio e/m:

$\displaystyle \frac{e}{m}=\sqrt{\frac{e}{m}}\frac{\sqrt{2V}}{RB}$

This, then, boils down to give e/m ratio in terms of V, r, and B, all of which are variables that we can find:

$\displaystyle \frac{e}{m}=\frac{2V}{(RB)^{2}}$

From here, we must find the strength of the magnetic field which is produced by the Helmholtz coils: We use the Biot-Savart Law, to find the field due to one coil, and then add the field due to two coils. A single coil, with N loops, of radius R, stands with its opening aligned with the y-axis. The point of interest will be at y=a. Due to symmetry, we know that there will only be a field in the positive y direction (where current flows counter-clockwise, as seen looking from positive y). Theta will rotate in the xz plane, which will allow us to define a small current element. Biot-Savart Law:

$\displaystyle d\vec{B}=\frac{\mu_{0}i}{4\pi}\frac{ \vec{dl}\times\vec{r}}{r^{3}}$

we know that dl is perpendicular to r always, and so we can turn this into a scalar equation for the y coordinate.

$\displaystyle dl = R d\theta$

$\displaystyle B_{y}=\frac{N\mu_{o}i}{4\pi}\int_{0\leq\theta\leq2\pi}\frac{Rd\theta}{(a^{2}+R^{2})}\frac{R}{\sqrt{a^{2}+R^{2}}}$

$\displaystyle B_{y}=\frac{N\mu_{o}i}{4\pi}\frac{R^{2}}{(a^{2}+R^{2})^{\frac{3}{2}}}\int_{0\leq\theta\leq2\pi}d\theta$

$\displaystyle B_{y}=\frac{N\mu_{o}i}{2}\frac{R^{2}}{(a^{2}+R^{2})^{\frac{3}{2}}}$

Now, because we have 2 coils, which make up the Helmholtz coils, we simply multiply the above expression to find the field as a function of the current:

$\displaystyle B_{y}(i)=\frac{N\mu_{o}iR^{2}}{(a^{2}+R^{2})^{\frac{3}{2}}}$

with this information, we should be able to complete the lab.

## Experimental Setup

• UCHIDA YOKO e/m experimental apparatus. Model TG-13.

Heater connected to SOAR PS-3630. Accelerating Electrodes connected in series with AMPROBE multimeter and then to the Gilman power supply. Voltmeter jacks connected to BK Precision multimeter Helmholtz coils connected in series with FLUKE multimeter to SOAR 7403 DC Power Supply.

• SOAR DC Power supply rated 36V, 4A. Model Number PS-3630.

Connected in series with an ammeter/voltmeter and connected to the heater.

• SOAR 7403 DC Power supply rated 36V, 4A. Serial Number 303018.

Connected in series with an ammeter/voltmeter and connected to the Helmholtz coils.

• BK Precision Digital Multimeter Model Number 2831B.

Connected directly to the voltmeter jacks on the e/m experimental apparatus.

• (Gelman Instrument Company. Deluxe Regulated Power Supply rated 500V, 100mA.

Connected in series with an ammeter/voltmeter and connected to the electron gun.

• FLUKE 111 True RMS multimeter 10A fused. CATIII 600V.

Connected in series to the SOAR 7403 and e/m experimental apparatus.

• AMPROBE 37XR-A. TRUE RMS CATII 1000V, CATIII 600V. 10A Max fused

Connected in series between e/m apparatus and Gelman power supply.

• Cloth placed over the coils so that the electron beam can be seen later on in the experiment.

NOTE:

• During the second week, we set up everything the same as above, except for one exception. The BK percision multimeters appeared to be working incorrectly. Because of this, we set up an extra multimeter to measure the accelerating potential.
• AMPROBE 37XR-A. TRUE RMS CATII 1000V, CATIII 600V. 10A Max fused.

## Procedure

1.) Turn on SOAR PS-3630 PSU for heater to:

• 1.500A Rated. (.7A)
• 6.302V

Nothing connected to ground. This starts the heating of the filament. It starts radiating as it heats up.

2.) Turn on Gilman power supply for electron gun

• 200V (this will be changed as necessary when we carry out our experiments)
• .012mA (this will be changed as necessary when we carry out our experiments)

3.) Settings on e/m experimental apparatus:

• Current Adjust turned to zero at start. We will turn this up later on to get current flowing through the coils to bend the beam.
• Focus kept in place for now -- this will be changed to get a good beam later.
• Set to e/ SJK 23:23, 3 October 2008 (EDT)
23:23, 3 October 2008 (EDT)
I notice this sentence is not completed here...I'm guessing you guys used Paul's notebook to take the original notes? I think linking to the original notes (instead of copying them) would be fine. In either case, it's a good idea to look them over to correct mistakes like these (if you can remember what you meant to write).

You and Paul took great notes, and I put some comments in his book, potentially regarding stuff you both did. So make sure to look at those comments on his page. (Lots of positive comments and some negative)

## Experimental Procedure

• To measure the radius of the beam, we lined up the actual beam with the reflection on the mirror on the back of the apparatus. Our measurements were compared and we decided on a radius, and decided on a reasonable uncertainty.
• Possible Source of error: Our voltmeters accuracy doesn't go into the decimals.
• Each data point has an uncertainty of at least ±.1 cm because this is roughly the width of the beam. We will have to see later what kind of error this will produce on our measured e/m ratio. m experimental apparatus to e/m measure (instead of Electrical deflect).

## Data

Source of error: Our voltmeters accuracy doesn't go into the decimals. Each data point has an uncertainty of at least ±.1 cm because this is roughly the width of the beam

### Constant Current

• i=1.069A

1.)200V, 4.1±.1cm

2.)210V, 4.35±.1cm

3.)220V, 4.45±.1cm

4.)230V, 4.5±.1cm

5.)240V, 4.55±.1cm

6.)250V, 4.60±.1cm

7.)260V, 4.65±.1cm

8.)270V, 4.70±.1cm

9.)280V, 4.75±.2cm

10.) 290V, 4.80±.3cm

11.) 300V, 4.90±.3cm

At the end, the beam seemed to get a bit thicker. This introduced more uncertainty into our measurements.

### Constant Voltage

One source of experimental error: The beam seems like it is somewhat elliptical. The radius on the right is slightly smaller than on the left. We have decided to use only the left radius. This will definitely introduce uncertainty into our calculations. However, after rotating the bulb, we have a spiral forming. With the spiral, we cannot take any measurements because there is simply too much going on.

V=280V

1.)i=1.000A, 4.75±.2cm

2.)i=1.050A, 4.75±.2cm

3.)i=1.100A, 4.60±.1cm

4.)i=1.151A, 4.55±.2cm

5.)i=1.202A, 4.47±.1cm

6.)i=1.253A, 4.35±.1cm

7.)i=1.297A, 4.25±.2cm

8.)i=1.351A, 4.15±.2cm

9.)i=1.399A, 4.05±.2cm

10.)i=1.449A, 4.00±.2cm

ANOTHER ROUND OF DATA FOR CONSTANT VOLTAGES:

• We repeated this in attempt to get better measurements. However, the circle keeps moving laterally. We will re center the ring each time. Here we must assume that the beam is a perfect circle each time. The voltage across the coils was untouched.
• Another Source of error:The ruler is aligned with the center of the glass globe. Therefore, once the radius of the beam becomes too small, the beam is no longer aligned with the ruler. This could definitely cause error in our calculations. The diameter of the circle must be on the same horizontal plane for the measurements to be consistent.

V=299.8

1.)i=1.245A, R=3.90±.1cm

2.)i=0.989A, R=4.25±.2cm

• The above data was abandoned. At that high of a voltage, the radii was only reasonable for a small range of currents.

V=249.6V

1.)i=.997A, R=3.95±.1cm

2.)i=1.252A, R=3.70±.2cm

# LAB SUMMARY

SJK 00:34, 4 October 2008 (EDT)
00:34, 4 October 2008 (EDT)
I do want your lab summary to be on a separate page. And also, actually a bit more concise. You will want to have this much analysis written down in your lab notebook, but then you want to sumamarize it on a separate page. Check out PK's summary for an example.

## Lab Manual Questions

1. Why do we see the electron beam at all?

The visual beam that we see is merely the ionization of the helium gas caused by the electrons losing energy to the helium causing the helium to emit photons of such wavelength in the visible light spectrum.

2. We ignored the Earth’s magnetic ﬁeld in our procedure. How much error does this introduce into this experiment?

Using the website http://www.ngdc.noaa.gov/geomagmodels/IGRFWMM.jsp, you can get the magnectic field and its components of your location. The total magnetic field in Albuquerque is 50,292.7 nT, with components of 23,027.7 nT North, 3858.3 nT East, 23,348.7 nT Horizontal, and 44,544.3 nT Upward. Our apperatus was more or less aligned with the east component of the earths B-field so plugging this value in using 300 V will give a reasonable approximation of the error the earths field could have caused.

$\displaystyle R = \sqrt{\frac{2Vm}{e}}\frac{1}{B} = 15.15m$

This value is actually pretty large using MatLab paul analyzed this result which you can see in the data analysis section.

3. Suppose that protons were emitted in the vacuum tube instead of electrons. How would this effect the experiment?

Using the same formula as in question 2:

$\displaystyle \frac{R_{p}}{R_{e}}=42.81$

So other than the difference in polarity the major difference would be a much stronger magnetic field would be needed to bend the beam.

4. Show that if the magnetic ﬁeld is held constant, the time t required for an electron to make a complete circle in your e/m tube and return to the anode is independent of the accelerating voltage by deriving an expression for this time.

$\displaystyle T=\frac{2\pi R}{v}$

$\displaystyle R = \sqrt{\frac{2Vm}{e}}\frac{1}{B}$

$\displaystyle v = \sqrt{\frac{2eV}{m}}$

$\displaystyle T = \frac{2\pi m}{e B}$

## Data Analysis

SJK 00:06, 4 October 2008 (EDT)
00:06, 4 October 2008 (EDT)
• Data analysis was done using programs written by Paul Klimov(for MatLab code of programs used see Paul Klimov's Lab notebook under MATLAB CODE)

## Programs

Using data analysis programs written in MATLAB by Paul klimov we calculated least squares regressions for both sets of data, constant voltage and constant current. The program then calculated an e/m ratio for both sets of data using the formula that is shown in theory section.

## Margin of Error

As will be discussed later in sources of error we had uncertainty in all of our measurements. The most obvious reason being the width of the beam caused a minimum uncertainty of one millimeter, though we often had larger uncertainty either due to thicker beams caused by higher voltage, or simply a large discrepency between Paul's and my measurements.

## Constant Current

Using the MatLab programs, the following information was obtained:

• Slope: .0836 ± 0.00113e-4 m^2/V
• Corresponding e/m Ratio: 3.440955866544257e+11 C/kg
• Corresponding e/m Ratio with Earths Magnetic Field: 3.370766636622313e+11 C/kg
• Mean e/m Ratio:3.415607994557289e+11 C/kg
• Mean e/m Ratio with Earths Magnetic Field: 3.391161980958560e+11 C/kg
• Standard Deviation: .1538626188222192e+11 C/kg

Slope Modification: Paul also had Matlab modify the linear regresion to fit within the error bars that data is included here along with the modified graph, figure 1b.

• Modified Slope: 0836 + 0.00113e-4 m^2/V
• Modified Corresponding e/m Ratio:3.395065625434909e+11 C/kg

## Constant Voltage

• Slope:0=5.269 ± 0.1 e-2 m/A
• Corresponding e/m Ratio:3.315449555220567e+11 C/kg
• Corresponding e/m Ratio with Earths Magnetic Field: 2.879693734013608e+11 C/kg
• Mean e/m Ratio:3.258205230221071e+11 C/kg
• Mean e/m Ratio with Earths Magnetic Field: 3.237264954654076e+11 C/kg
• Standard Deviation: .4224672028400931e+11 C/kg

Slope Modification: Figure 2b

• Modified Slope: 5.369 e-2 m/A
• Modified Corresponding em ratio: 3.193096279082144e+11 C/kg

## Final Stats

SJK 23:46, 3 October 2008 (EDT)
23:46, 3 October 2008 (EDT)
There is missing any description of what "overall" and "best" mean. There are also the last two figures without any discussion of why or what they are.
• overall mean e/m ratio: 3.336906612389180e+11 C/kg
• overall mean e/m ratio with earths magnetic field:3.314213467806318e+11 C/kg
• overall standard deviation: .3140717276887458e+11 C/kg
• overall mean percent error: 89.99%
• overall mean percent error with earths magnetic field:88.70%

• best e/m ratio: 2.739946406166065 C/kg
• best e/m ratio with earths magnetic field: 2.725458559266957 C/kg
• best percent error: 56.01%
• best percent error with earths magnetic field:55.18%

## Sources of Error

SJK 00:01, 4 October 2008 (EDT)
00:01, 4 October 2008 (EDT)
This is a good discussion of error sources.

This lab we were told has one of the worst percentage errors of any of the labs we will be doing this semester. With that in mind we watched very closely for sources of this while doing the lab.