Objective
- Prepare heavy metal solutions (Zn, Pb, Cu)
Description
- Prepare 100mL of 100ppm solutions of Pb, Zn, Cu
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- 100mL*1L/1000mL*100mg Cu/1L*134.45 g/mol CuCl2/63.54 g/mol Cu = 21.16 mg CuCl2
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- 100mL*1L/1000mL*100mg Pb/1L*325.29 g/mol PbAc/207.2 g/mol Cu = 15.7 mg PbAc
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- 100mL*1L/1000mL*100mg Zn/1L*138.315 g/mol ZnCl2/65.38 g/mol Zn = 21.15 mg ZnCl2
- Prepare 50mL of 300 ppm metals (100ppm Pb, 100ppm Zn, 100ppm Cu)
- 10.58 mg CuCl2
- 10.57 mg ZnCl2
- 7.85 mg PbAc
- 50mL H2O
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- 10mL of 300ppm and 40mL water
Dry:15.5904g
Wet: 15.9570g
W/Beads: 16.65g
Dry:15.966g
Wet: 16.389g
W/Beads: 17.55g
Ran data analysis on 10% beads with MG
- Found the Max Absorbance for each run.
- Using the Beer's Law calibration Curve we found a few weeks ago (y=0.0813x) calculated concentration for each sample.
- Created plot of concentration vs. Volume Eluted.
- Calculated the amount of MG added to the Column
- 54 samples *5mL/sample*1L/1000mL*50mg/1L = 1.75mg
- Calculated the amount of MG eluted.
- From samples 1-54:
- 5mL*1L/1000mL*concentration of sample = mg of MG not adsorbed
- For sample 55:
- 1mL*1L/1000mL*concentration of sample = mg of MG not adsorbed
- 4mL*1L/1000mL*concentration of sample = mg of MG desorbed
- For samples 56-88:
- 5mL*1L/1000mL*concentration of sample = mg of MG desorbed
- Subtract mg of MG not adsorbed from amount of MG added to column to get amount of MG adsorbed by the column.
- Find capacity of beads by dividing mass of MG adsorbed by mass of beads
- Find capacity of activated carbon by dividing mass of MG adsorbed by mass of activated carbon in beads.
Data
Data and Results for 10% Column with MG
Graph of Concentration of MG vs. Volume of MG Eluted
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Amount of MG loaded: 13.5mg
Amount not adsorbed: 0.6025mg
Amount adsorbed: 13.5mg-0.6025mg=12.9mg
Amount desorbed: 0.2879mg
Mass of Wet Beads in Column: 1.465g
Mass of Dry Beads in Column: 0.2683g
Capacity of Beads: 48.08 mg/g
Mass of Clay in Column: 0.02683g
Capacity of Clay: 480.8 mg/g
Swelling for 10% clay is 446%
- 4.46=wet-dry/dry
- 4.46*dry = wet-dry
- 4.46dry+dry= wet
- 5.46dry = wet
- wet = 1.465g
- 1.465/5.46 = dry
- dry mass = 0.2683g
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