Objective
- synthesize AUNP at a concentration of 60 HAUCl4 to 1 BSA
- prepare stock solutions
Description
- Stock Solutions
- HAuCl4 in 50mL solution
- 2.7mM= 0.0027mols/L x 0.05 L = 1.35E-4 mols HAuCl4
- 1.35E-4 mols HAuCl4 x 337.79 mols = 0.0458789 grams of HAuCl4
- BSA in 50mL solutions
- 1.5µM=0.000015mols/L x 0.05L = 7.5 E-7 mols
- 7.5 E-7 mols x 66,000 g/mol = 0.0495 grams of BSA
- BSA/AuNP Preparation of 60:1 based off stocks above
Calculations for dilutions of 60:1 in 10 mL
- (0.906ml HAuCl4)(0.0027mols/L)= (10mL)(x)
- x=0.000245mols/L of HAuCl4 in 10mL of water total volume
- (x)(.000015mols/L)=(10mL)/(0.000004 mols/L)
- x= 2.666 mL of BSA in 10mL of water total volume
- So,
- 2666 µL of HAuCl4
- 906 µL of BSA
- 6428 µL of H20
Check on ratio of concentration= (0.000009mols/L)/ (0.00000015mols/LBSA) = 60/1
Data
- nothing, bsa stock was to dilute to produce any nano particles
Notes
- No nano particles were made due to lack of HAuCl4.
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