IGEM:UNAM/2009/Notebook/Modeling logbook Claudia/2010/04/06
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Objective: Calculate the photon flux that saturates the LovTAP receptor.In Strickland et al. is reported that LovTAP is saturated with 20 mW/cm^2 irradiance at 470 nm.
The energy E of a photon is E = hc / λ where h is Planck's Constant, h = 6.626176 x 10^-34 J•s The velocity of any photon is c, the speed of light=3 * 10^8 m/ s And λ the wavelength of the photon that in this case is 470 x 10^-9 m (470 nm). Thus, E= ((6.63 * (10^(-34))) * (3 * (10^8))) / (470 * (10^(-9))) E= 4.23191489 × 10^-19 J
The photon flux density (Φ ) at a given light intensity is: Φ= P/ E where P is the light intensity in Watts and E the energy of a photon in Jules. Substituting: P= 0.02 Watts and E= 4.23191489 × 10^-19 J. Φ= 0.02/ (4.23191489 * 10^-19 ) = 4.72599297 × 10^16 photons/s•cm2 ReferencesStrickland, D., Moffat, K., & Sosnick, T. (2008). Light-activated DNA binding in a designed allosteric protein. Proceedings of the National Academy of Sciences, 105(31), 10709. National Acad Sciences. Retrieved from http://www.pnas.org/content/105/31/10709.full.
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