User:Alicia Rasines Mazo/Notebook/CHEM-581 Experimental Chemistry I/2014/09/05: Difference between revisions
From OpenWetWare
No edit summary |
(fix raw html notebook nav) |
||
(3 intermediate revisions by one other user not shown) | |||
Line 2: | Line 2: | ||
|- | |- | ||
|style="background-color: #EEE"|[[Image:owwnotebook_icon.png|128px]]<span style="font-size:22px;"> Project name</span> | |style="background-color: #EEE"|[[Image:owwnotebook_icon.png|128px]]<span style="font-size:22px;"> Project name</span> | ||
|style="background-color: #F2F2F2" align="center"| | |style="background-color: #F2F2F2" align="center"|[[File:Report.png|frameless|link={{#sub:{{FULLPAGENAME}}|0|-11}}]][[{{#sub:{{FULLPAGENAME}}|0|-11}}|Main project page]]<br />{{#if:{{#lnpreventry:{{FULLPAGENAME}}}}|[[File:Resultset_previous.png|frameless|link={{#lnpreventry:{{FULLPAGENAME}}}}]][[{{#lnpreventry:{{FULLPAGENAME}}}}{{!}}Previous entry]] }}{{#if:{{#lnnextentry:{{FULLPAGENAME}}}}|[[{{#lnnextentry:{{FULLPAGENAME}}}}{{!}}Next entry]][[File:Resultset_next.png|frameless|link={{#lnnextentry:{{FULLPAGENAME}}}}]]}} | ||
|- | |- | ||
| colspan="2"| | | colspan="2"| | ||
Line 56: | Line 56: | ||
** 2 ppm - 0.0696 = 1.9304 ppm of MG absorbed | ** 2 ppm - 0.0696 = 1.9304 ppm of MG absorbed | ||
** (1.9304 mg MG)/(L solution) × 0.010 L solution = 0.0193 mg MG/film | ** (1.9304 mg MG)/(L solution) × 0.010 L solution = 0.0193 mg MG/film | ||
** Since the clay film weighed 0.1286 g, the amount of MG dye absorbed in the polymer film into 2 ppm MG green solution is (0.0193 mg MG)/(0.1286)=0. | ** Since the clay film weighed 0.1286 g, the amount of MG dye absorbed in the polymer film into 2 ppm MG green solution is (0.0193 mg MG)/(0.1286)=0.00015 mg MG/mg polymer film. | ||
*'''PVA film in 8 ppm MG''' | |||
** 0.0013 mg MG/mg PVA film | |||
*'''PVA film in 80 ppm MG''' | |||
** 0.0049 mg MG/mg PVA film | |||
*'''PVA film in 200 ppm MG''' | |||
** 0.0121 mg MG/mg PVA film | |||
<br.> | <br.> | ||
*'''PVA film in 8 ppm MG''' | *'''PVA-Clay film in 2 ppm MG''' | ||
** 0.00029 mg MG/mg PVA-Clay film | |||
**'''PVA-Clay film in 8 ppm MG''' | |||
** 0.0012 mg MG/mg PVA-Clay film | |||
*'''PVA-Clay film in 80 ppm MG''' | |||
** 0.0099 mg MG/mg PVA-Clay film | |||
*'''PVA-Clay film in 200 ppm MG''' | |||
** 0.0177 mg MG/mg PVA-Clay film | |||
===FTIR Analysis of Films with MG dye=== | |||
[[Image:FTIR 2 050914.jpeg]] | |||
[[Image:FTIR 1 050914.png]] | |||
[[Image:FTIR 050914.png]] | |||
<!-- ##### DO NOT edit below this line unless you know what you are doing. ##### --> | <!-- ##### DO NOT edit below this line unless you know what you are doing. ##### --> | ||
__NOTOC__ | __NOTOC__ |
Latest revision as of 00:14, 27 September 2017
Project name | Main project page Previous entry Next entry |
Tasks for 5 September 2014
New Film synthesis
UV-Vis analysis of MG leftover solutions
<br.> From this, it can be seen that there are two major peaks at 425 nm and 615 nm. <br.> These calibrations curves show that the molar absorptivity at 425 nm is 0.0266 M-1cm-1 and 0.1293 M-1 cm-1 at 615 nm.
<br.> Using Beer-Lambert's Law, the concentrations of leftover dye in solution were calculated:
Determining the amount of MG dye absorbed per mg of filmNote, the results were calculated using 615 nm values
<br.>
FTIR Analysis of Films with MG dye
|