User:Klare Lazor/Notebook/Chem-496-001/2013/02/11

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  1. crosslinking films from friday and dsc
  2. remaking films with lower molecular weight and phenol
  3. Discussing with fox about the failure of the synthesis of the quaternary amine


Film description from 7/8 Friday

  • 1% Phenol looked the best for the film with mw: 146,000-186,000
  • .1% and 10% crystals were forming either phenol or pvoh or both
  • concluded to high of a molecular weight the crystals were most likely pvoh recrystalizing
  • will still attempt to crosslink and dsc on the flat areas of the films
  • bubbles from the high molecular weight may have also lead to less mixing and crystal formation

Cross-linking PVOH (MW:146,000-186,000) Films With 0.7M HCl and neutralizing .6 Molar sodium bicarbonate

  • To high of a molecular weight will remake with with a lower molecular weight
  • MW: 22,000 will be used instead for this....higher molecular weight is to thick for this type of reaction with crosslinking with glutaraldehyde
  • 20ml of 100% H2So4 in 1 L of H20 was use for the fixant will determine amount of H+ ions in solution to determine concentartion of HCL
    • 20ml* 1.84g/ml ÷ 98.079g/mol = 0.375moles of H2SO4 ÷ 1 Liter= 0.369 Molar H2SO4
    • assume complete dissociation
    • 0.369mols of H2SO4/L * 2mols HCl/1mol of H2SO4 = 0.7M HCl, which is equal to 6ml of 12 M HCl in 94 ml of H2O for 1 Hour
  • To neutralize a NaHCO3 solution will be made, 0.7 M NaHCO3 15 minutes

Switching to lower molecular weight: PVOH (MW: 22,000) + phenol + glutaraldehyde + 30 ml of water

  • 22,000 MW PVOH → 44g/mol
  • 1 gram PVOH/ 22,000g/mole = 4.57E-5 m oles PVOH
  • 22,000 g/mol PVOH / 44 g/mol = 500 OH groups per a molecule of PVOH
  • 4.54E-5moles PVOH * 5000 oh groups/molecule of PVOH * 6.002 E23 molecules/mol = 1.369 E 22 oh groups in 1 gram of PVOH 22000 mw
  • we want one OH in Phenol to react with 10%, 1%,.1% and 0.01% of oh groups in PVOH
  • used the 10% stock left over from last time and reduce by a factor of ten for each percentage
    • 1%= 1ml of stock
    • .1%=0.1ml of stock
    • .01%= 0.01 ml of stock
    • 10%= whatever ml left over will end up close to 10% will calculate after measuring how much stock is left over