User:Klare Lazor/Notebook/Chem-496-001/2013/02/07

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Making PVOH/Glutaraldehyde/Phenol Films:

  1. Fill 5 50mL beakers with 15mL HPLC water. Place on hot/stir plates in the hood.
  2. Measure out 1g of PVOH (5 times) and place into the 5 beakers (1g each). Allow PVOH to begin dissolving on hot/stir plates.
  3. Measure out 2.1457g Phenol, 0.21457g Phenol, 0.021457g Phenol, and 0.00257g Phenol (for the latter I prepared a solution of 10mL and 0.22g Phenol and used 1mL [for 0.022g] and 0.1mL [for 0.0022g]). Add each measurement of phenol to 4 of the beakers with PVOH respectively.
  4. Allow mixtures of PVOH, Phenol, and water to stir on hot/stir plate until fully dissolved.
  5. Once full dissolution is achieved, add 1mL Glutaraldehyde to each of the 5 beakers. Allow to stir off heat for 2-3 minutes.
  6. Pour solutions into labeled film dishes.


Notes on Phenol Safety Procedure: Keep Phenol under hood at all times. Use FULL protective gear to avoid touching or breathing the phenol. Wash all dishes that have touched phenol thoroughly and pour waste water in a labeled waste container. Clean up ANY and ALL phenol that spills thoroughly. Throw away all solid waste that has touched phenol in a labeled solid waste container.

Notes on Films: These films did not form as well as hoped. 2 of the solutions (the 0.214g Phenol and the 0.0214g phenol) dissolved but then began to form many bubbles in them. The films therefore look somewhat white with bubbles. The 2.15g phenol solution had a lot of trouble dissolving, furthermore the phenol was a little brown almost immediately on being added to the solution. An extra 5 mL was added to this solution to aid dissolution.

Calculations: There are 6.86508E21 OH groups n 0.5g PVOH (from previous days' calculations) * 2 = 1.373E22 OH groups in 1g PVOH We want films in which 10%, 1%, 0.1%, and 0.01% of PVOH OH groups react with OH groups in phenol.

10%) 1.373E22 OH groups in 1g PVOH * 0.1 = 1.373E21 NOTE***** I just noticed I made a calculation mistake and in my original calculations had this equaling 1.373E23, 100x the actual amount. This number is then divided by 6.022E23 and multiplied by the molecular weight of Phenol (94.11). Therefore all of my phenol amounts added should have been less by a factor of 100. We will therefore redo the 0.1% and 0.01% films properly [the 0.1% and 0.01% solutions are ACTUALLY 10% and 1%].