User:Dhea Patel/Notebook/Phosphorylation/2012/06/21

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0.06229 g ÷ 898.65 g/mol RuComp × 1000 mmol/mol = 0.06932 mmol Ru Complex

1:1 Ru:ATP

0.06932 mmol ÷ 1000 mmol/mol × 507.18 g/mol = 0.0352g ATP

0.0352g ATP ÷ 507.18g/mol ATP × 0.596 mol DCC ÷ 0.197 mol ATP × 206.33g/mol DCC = 0.04332g DCC


  1. The 0.0352g of ATP was dissolved in 0.1M TEAB and run in a column using 0.1M TEAB, collecting 5mL fractions.
  2. The fractions were spotted on a TLC plate and UV was used to determine which fractions contained ATP.
  3. Fractions 2, 3, and 4 contained ATP. These fractions were combined and rotovapped. The ATP was not visible after the rotovap.
  4. 10mL methanol was added and rotovapped (three times). (Once again, the ATP did not seem visible after the rotovap.)
  5. 1.8 mL DMF was added under Nitrogen
  6. A drop of DMF-ATP was spotted on a TLC plate, indicating the presence of ATP
  7. 0.04332 g DCC was added and the reaction ran for 3 hours.
  8. 0.06229g Ru Complex was dissolved in 10mL MeOH and added to ATP after the 3-hour reaction was completed.
  9. 0.25mL TEA was added to the mixture under Nitrogen and reacted for 30 minutes.
  10. 20mL of H2O was added (no longer under nitrogen) and the mixture was covered overnight.
  11. When the mixture was added to the water, a cloudy orange-yellow solution precipitates, which had not occurred before. Perhaps this was because of the 1:1 ratio.
  12. The solution was covered and left under the hood overnight.


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