Difference between revisions of "User:Mobeen Ashraf/Notebook/Chem-581/2012/10/31"

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==Objective==
 
==Objective==
  
Objective 1) Prepare 3 PVOH Films (plain MW 22,000, glutaraldehyde cross-linked, and porphyrine dihydrogen chloride cross-linked.  
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Catalysis and Stimulation of Cross-Linking Studies.
  
Objective 2) Atomic Absorption Spectroscopy for all Cu standards.
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==Description==
  
==Description==
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*6 molal NaCl solution was prepared. Porphyrin was submerged in the solution for an hour at 70 degrees Celsius under constant stirring.
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* 6 m NaCl solution was prepared in a following manner:
  
* 3 PVOH films were prepared: 0.5 g MW of 22,000, 1 ml glutaraldehyde, and 1 ml of porphrine dihydrogen chloride.  
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(6 mol/1Kg H2O) * (57.54 g NaCl/mol NaCl) = 345.24 g NaCl/1 Kg of H2O. 1 Kg of water is equivalent to 1,000 mL of H2O. Therefore, 6 m NaCl solution should be equivalent to 34.5 g NaCl/100 mL H2O.
* AAS studies for all the Cu standards: NaMT- concentration of 1.25 g/500 ml, for 1min, 5 min and 10 mins standards, 50 % CEC exchange-concentration of 1.25 g/500 ml, for 1 min, 5 min and 10 mins standards, 100% CEC exchange, for 1 min, 5 min and 10 mins standards, and Fe3O4-concentration of 1.25 g/500 ml, for 1 min, 5 min and 10 mins standards.
 
  
 
==Data==
 
==Data==

Revision as of 11:04, 28 November 2012

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Objective

Catalysis and Stimulation of Cross-Linking Studies.

Description

  • 6 molal NaCl solution was prepared. Porphyrin was submerged in the solution for an hour at 70 degrees Celsius under constant stirring.
  • 6 m NaCl solution was prepared in a following manner:

(6 mol/1Kg H2O) * (57.54 g NaCl/mol NaCl) = 345.24 g NaCl/1 Kg of H2O. 1 Kg of water is equivalent to 1,000 mL of H2O. Therefore, 6 m NaCl solution should be equivalent to 34.5 g NaCl/100 mL H2O.

Data

  • Add data and results here...

Notes

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