Objective
- Prepare stock solutions of HAuCl4 and BSA and use them to make solutions of HAuCl4 and BSA at varying mole ratios.
- These are to be analyzed by UV/Vis next week to find the optimal mole ratio for nucleation of gold nanoparticles.
Procedure
- 25mL of stock solution of 7.721mM HAuCl4 was prepared.
- (moles HAuCl4)/.025L H2O = .01M
- 2.5*10-4 mol HAuCl4 is the amount of gold needed to make this concentration with .025L
- 2.5*10-4 mol * 339.785mol/g HAuCl4 = .0849g HAuCl4 is needed
- .0197g of the .0849g stuck to the weigh paper, leaving .0656gHAuCl4.
- .0656g HAuCl4 * (1molHAuCl4/339.79g/molHAuCl4)= xM HAuCl4
- .007721M HAuCl4 was the molarity of stock solution made
- .0849g HAuCl4 was put in 25mL to make a 10mM solution
- 25mL stock solution of 15μM BSA was prepared
- (moles BSA)/.025L = .000015
- 3.75*10^-7mol BSA is the amount of BSA needded to make a 15μM solution with .025L.
- 3.75*10^-7mol BSA * 66,463g/mol BSA = .0249g BSA needed
- .0249g BSA was put in 25mL to make a 15μM solution
- 6mL solutions were prepared with the mole ratios of (HAuCl4/BSA) 60, 80, 100, 120, 128, 130, 132, 133, 134, 136, 138, 140, 160, and 170. .6mL of HAuCl4 stock was added to each tube, so each was 1.5mM HAuCl4
- The formula m1v1=m2v2 was used to determine how much BSA was needed for mole ratios (BSA/Au) of 60-170
- 15μM*(volume BSA stock solution) = (1.5*6)
- 0.6mL BSA stock solution in each tube
- 7720μM*x mL=6mL*(1.5*60μM)
- 0.069mL HAuCl4 stock solution
- 5.331 mL H2O
- 7720μM*x mL=6mL*(1.5*80μM)
- 0.093mL HAuCl4 stock solution
- 5.307mL H2O
- 7720μM*x mL=6mL*(1.5*100μM)
- 0.117mL HAuCl4 stock solution
- 5.283mL H2O
- 7720μM*x mL=6mL*(1.5*120μM)
- 0.134mL HAuCl4 stock solution
- 5.266mL H2O
- 7720μM*x mL=6mL*(1.5*128μM)
- 0.149mL HAuCl4 stock solution
- 5.251mL H2O
- 7720μM*x mL=6mL*(1.5*130μM)
- .152mL HAuCl4 stock solution
- 5.248mL H2O
- 7720μM*x mL=6mL*(1.5*132μM)
- 0.154mL HAuCl4 stock solution
- 5.246mL H2O
- 7720μM*x mL=6mL*(1.5*133μM)
- 0.155mL HAuCl4 stock solution
- 5.245mL H2O
- 7720μM*x mL=6mL*(1.5*134μM)
- 0.156mL HAuCl4 stock solution
- 5.254mL H2O
- 7720μM*x mL=6mL*(1.5*136μM)
- 0.159mL HAuCl4 stock solution
- 5.244mL H2O
- 7720μM*x mL=6mL*(1.5*138μM)
- 0.161mL HAuCl4 stock solution
- 5.242mL H2O
- 7720μM*x mL=6mL*(1.5*140μM)
- 0.163mL HAuCl4 stock solution
- 5.237mL H2O
- 7720μM*x mL=6mL*(1.5*160μM)
- 0.187mL HAuCl4 stock solution
- 5.213mL H2O
- 7720μM*x mL=6mL*(1.5*170μM)
- 0.198mL HAuCl4 stock solution
- 5.202mL H2O
- The tubes were capped with tin foil and heated at 85°C for 4 hours.
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