User:Melissa Novy/Notebook/CHEM-572/2013/02/13

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Objectives

  • Insert content here...

0.1 M AgNO3

  • Calculations
  250 mL of 0.1 M AgNO3
  MW AgNO3 = 169.87 g/mol
  0.1 M × 0.250 L = 0.025 mol
  0.025 mol AgNO3 × (169.87 g AgNO3/1 mol AgNO3) = 4.24675 g AgNO3
  • Actual mass AgNO3: 4.24694 g
  • Actual molarity AgNO3: 0.10000 M AgNO3