- In reference to the PCR Mutation protocol, 100 ng/μL of the primer was needed for the reaction. The weight of the primer in the provided container was 0.46 mg. A ratio of the weight over volume was equated to the required concentration of the primer:
0.46 mg = 0.46E6 ng
= of primer in water = 4600 μL of water
- There is limited space in the plastic container (1 mL). Instead of dissolving 0.46E6 ng of the primer in 4600 μL of water, the entire primer was dissolved in 1 mL water.
- Using M1V1 = M2V2, the volume taken from the solution of 0.46E6 ng in 1 mL of water was calculated to be 217.39 μL. This was transferred to a new tube and filled up with water to a total volume of 1 mL.
V1 = = 217.39 μL of the dissolved primer in water
- The procedure listed in PCR Mutation protocol was strictly followed. After the addition of all reagents, the sample was placed in the thermocycler.
Continuation of Chemiluminescence
- The luminol prepared from the previous chemiluminescence laboratory period had a pH of 7 to 8. Reviewing a journal article of Xiaoyu, it was determined that the optimal pH of luminol was 12.5. As a result, it was decided to prepare a new solution of luminol at a pH of 10 to 11.
- A weight of .0112 g of luminol was added to 6 mL of water. The buffer composed of a direct addition of .0737 g of sodium carbonate and .4358 g of sodium bicarbonate.
- Using a pH meter, the electrode detected the pH at 8.73. As suggested by Dr. Hartings, a solution of sodium carbonate was made to increase the pH of the solution.
- Several adjustments were made in increasing the pH. A total weight of 1.91 g of sodium carbonate dissolved in 15 mL of water was added to the 6 mL solution of luminol.
- The molarity of sodium carbonate (MW 105.9784 g/mol) added was calculated:
× = × = = 1.20 M of sodium carbonate
- The concentration of luminol has been diluted by the addition of 15 mL of water.
Molarity of diluted luminol = = 2.85714 mM of luminol
- Since there was limited amounts of the solid form of luminol, it was decided to take 6 mL of the 2.86 mM luminol stock solution and then add the appropriate amount of luminol to the 6 mL volume. The molarity of the 6 mL solution was very minute; the molarity was approximated as 2 mM. By making this assumption, .00106 g of luminol would make a 1 mM solution in 6 mL of water; this amount was multiplied by 8. The product was 0.00848 g of luminol was needed to be added into the 2 mM solution of luminol to increase the molarity to 10 mM.