Difference between revisions of "User:Mary Mendoza/Notebook/CHEM572 Exp. Biological Chemistry II/2013/01/23"

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(Calculation of reagents for ADA kinetic assay)
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* It was decided to prepare a 30 mM stock solution of adenosine. The calculation below shows the amount needed to obtain 30 mM of adenosine.
 
* It was decided to prepare a 30 mM stock solution of adenosine. The calculation below shows the amount needed to obtain 30 mM of adenosine.
  
<math>.030/frac{mol}{L} of adenosine</math>
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.030  <math>\frac{mol}{L}</math> mol of adenosine × <math>\frac{267.24  g}{1  mol}</math> = <math>\frac{8.0172 g}{L}</math> × .010 L = 0.0802 g of adenosine
  
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The calculations on the bottom are courtesy of [[User:Dhea Patel/Notebook/CHEM 572: ADA&Inhibitor Kinetics/2013/01/23|Dhea Patel]].
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[[Image:ADA_kinetics_table.png|px80]]
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The calculation of for the buffer was formulated by [[User:Catherine Koenigsknecht/Notebook/Experimental Biological Chemistry/2013/01/23|Catherine Koenigsknecht]].
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* Procedure: Buffer
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#Protocol for 0.1 M Sodium Phosphate Buffer (pH 7.4)
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#Add 3.1 g of NaH2PO4•H2O and 10.9 g of Na2HPO4 (anhydrous) to distilled H2O to make a volume of 1 L. The pH of the final solution will be 7.4. This buffer can be stored for up to 1 mo at 4°C.
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#Dilute to 0.05M: (take 50 mL of 1M solution and dilute in 1 Liter H2O)
  
 
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Calculation of reagents for ADA kinetic assay

  • It was decided to prepare a 30 mM stock solution of adenosine. The calculation below shows the amount needed to obtain 30 mM of adenosine.

.030 Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://api.formulasearchengine.com/v1/":): {\displaystyle \frac{mol}{L}} mol of adenosine × Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://api.formulasearchengine.com/v1/":): {\displaystyle \frac{267.24 g}{1 mol}} = Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://api.formulasearchengine.com/v1/":): {\displaystyle \frac{8.0172 g}{L}} × .010 L = 0.0802 g of adenosine


The calculations on the bottom are courtesy of Dhea Patel.

px80


The calculation of for the buffer was formulated by Catherine Koenigsknecht.

  • Procedure: Buffer
  1. Protocol for 0.1 M Sodium Phosphate Buffer (pH 7.4)
  2. Add 3.1 g of NaH2PO4•H2O and 10.9 g of Na2HPO4 (anhydrous) to distilled H2O to make a volume of 1 L. The pH of the final solution will be 7.4. This buffer can be stored for up to 1 mo at 4°C.
  3. Dilute to 0.05M: (take 50 mL of 1M solution and dilute in 1 Liter H2O)