Difference between revisions of "User:Mary Mendoza/Notebook/CHEM572 Exp. Biological Chemistry II/2013/01/23"
Mary Mendoza (talk  contribs) (→Calculation of reagents for ADA kinetic assay) 
Mary Mendoza (talk  contribs) (→Calculation of reagents for ADA kinetic assay) 

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* It was decided to prepare a 30 mM stock solution of adenosine. The calculation below shows the amount needed to obtain 30 mM of adenosine.  * It was decided to prepare a 30 mM stock solution of adenosine. The calculation below shows the amount needed to obtain 30 mM of adenosine.  
−  .030 <math>\frac{mol}{L}</math> mol of adenosine × <math>\frac{267.24 g}{1 mol}</math> = <math>\frac{8.0172 g}{L}</math> × .010 L = 0.0802 g  +  .030 <math>\frac{mol}{L}</math> mol of adenosine × <math>\frac{267.24 g}{1 mol}</math> = <math>\frac{8.0172 g}{L}</math> × .010 L = 0.0802 g of adenosine 
Revision as of 12:23, 23 January 2013
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Calculation of reagents for ADA kinetic assay
.030 Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://api.formulasearchengine.com/v1/":): {\displaystyle \frac{mol}{L}} mol of adenosine × Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://api.formulasearchengine.com/v1/":): {\displaystyle \frac{267.24 g}{1 mol}} = Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://api.formulasearchengine.com/v1/":): {\displaystyle \frac{8.0172 g}{L}} × .010 L = 0.0802 g of adenosine
