User:Klare Lazor/Notebook/Chem-496-001/2013/02/25: Difference between revisions
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==Description== | ==Description== | ||
'''Procedure''' | |||
To eventually attach a protein, we can not crosslink in acidic or heated conditions. Therefore, for this procedure. We will be using hydrogels instead. 4 hydrogels were prepared. 2 were made using PVOH MW = 22,000, while the other two were made using PVOH MW = 146,000 - 186,000. For each molecular weight, one hydrogel was made with isopropanol alone, and one was made with isopropanol + glutaraldehyde. The amounts of isopropanol used is the same as in previous trials. | |||
# Measure out 2 samples of 1 g PVOH (MW = 22,000) and 2 samples of 1 g PVOH (MW = 146,000 - 186,000) | # Measure out 2 samples of 1 g PVOH (MW = 22,000) and 2 samples of 1 g PVOH (MW = 146,000 - 186,000) | ||
# Dissolve in 20 mL water (Dissolve on heat) | # Dissolve in 20 mL water (Dissolve on heat) | ||
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# 1 mL glutaraldehyde was added to the 2 hydrogels that are isopropanol + glut | # 1 mL glutaraldehyde was added to the 2 hydrogels that are isopropanol + glut | ||
# The hydrogels were placed in the freezer for 24 hours out for 4 hours in for 24hours and then out once again. repeated cycles. | # The hydrogels were placed in the freezer for 24 hours out for 4 hours in for 24hours and then out once again. repeated cycles. | ||
'''Calculations''' | |||
2 hydrogels of 22k MW PVOH and 2 hydrogels of 146-186k MW PVOH. All will have 1% isopropanol: PVOH OH groups. 1 of each will have glutaraldehyde (1mL). | |||
From previous calculations, 1g PVOH contains 1.373E22 OH groups. We want 1% of these to react w isopropanol at 1:1. (1.373E22)(0.01)=1.373E20 molecules of isopropanol. (1.373E20)/(6.022E23 molecules per mole)=2.27997E-4 moles isopropanol. (2.27994E-4 moles)(60.1 grams per mole)=0.0137 grams isopropanol. (0.0137g)/(0.786 grams per mL)=0.0174mL Isopropanol. | |||
# 1g 22000mw PVOH dissolved in 20mL distilled water + 0.0174mL Isopropanol once PVOH fully dissolved. Poured into dish, sealed with parafilm, and placed in freezer. | |||
# 1g 22000mw PVOH dissolved in 20mL distilled water + 0.0174mL Isopropanol and 1mL glutaraldehyde (in hood) once PVOH fully dissolved. Poured into dish, sealed with parafilm, and placed in freezer. | |||
# 1g 146-186K mw PVOH dissolved in 30mL distilled water + 0.0174mL Isopropanol once PVOH fully dissolved. Poured into dish, sealed with parafilm, and placed in freezer. | |||
# 1g 146-186K mw PVOH dissolved in 30mL distilled water + 0.0174mL Isopropanol and 1mL glutaraldehyde (in hood) once PVOH fully dissolved. Poured into dish, sealed with parafilm, and placed in freezer. | |||
==Data== | ==Data== |
Revision as of 21:30, 27 February 2013
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ObjectiveHydrogels for eventual attachment of protein DescriptionProcedure To eventually attach a protein, we can not crosslink in acidic or heated conditions. Therefore, for this procedure. We will be using hydrogels instead. 4 hydrogels were prepared. 2 were made using PVOH MW = 22,000, while the other two were made using PVOH MW = 146,000 - 186,000. For each molecular weight, one hydrogel was made with isopropanol alone, and one was made with isopropanol + glutaraldehyde. The amounts of isopropanol used is the same as in previous trials.
Calculations 2 hydrogels of 22k MW PVOH and 2 hydrogels of 146-186k MW PVOH. All will have 1% isopropanol: PVOH OH groups. 1 of each will have glutaraldehyde (1mL). From previous calculations, 1g PVOH contains 1.373E22 OH groups. We want 1% of these to react w isopropanol at 1:1. (1.373E22)(0.01)=1.373E20 molecules of isopropanol. (1.373E20)/(6.022E23 molecules per mole)=2.27997E-4 moles isopropanol. (2.27994E-4 moles)(60.1 grams per mole)=0.0137 grams isopropanol. (0.0137g)/(0.786 grams per mL)=0.0174mL Isopropanol.
Data
NotesThis area is for any observations or conclusions that you would like to note.
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