User:Karlena L. Brown/Notebook/PVOH Research/2012/11/09

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Revision as of 11:38, 30 November 2012 by Karlena L. Brown (talk | contribs) (Acetylation Reaction Calculations)
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OBJECTIVES

  • Prepare PVOH films for Acetylation Reactions

Acetylation Reaction Protocol & Film Preparation

  • In 10mL beaker, weigh out ~ 1.0 grams PVOH (MW 22K)
  • Then, using a graduated cylinder add ~ 5 mL H2O to the beaker
  • After adding and combining PVOH (MW 22K) in a small beaker with H2O, add a stir bar and prepare to stir solution
  • On hot plate, stir and heat beaker solutions at 70-80°C for ~ 12 min or until PVOH dissolves
  • Once PVOH solids thoroughly dissolve in solution, add a small portion of acetic acid (HoAc)
  • In addition, add ~2 drops of HCl to the solution and continue to stir for an hour
  • Allow the solution to cool and prepare for titration

REPEAT PROCEDURE ABOVE FOUR TIMES TO PREPARE FOUR FILMS

PVOH Mass (g) Acetic Acid (mL) Hydrochloric Acid (drops)
1.0062 1.30 2
1.0043 0.26 2
1.0052 0.52 2
1.0027 0.78 2


Acetylation Reaction Calculations

1:1 HoAc Reaction Ratio:

  MW R-CH2CHOH-R: 44.00 g/mol
  MW Acetic Acid (HoAc): 60.00 g/mol
  1.0g PVOH × (1 mol PVOH/44.00g PVOH) × (1 mol HoAc/1 mol PVOH) × (60.00g HoAc/1 mol HoAc) = 1.36g HoAc
  1.36g HoAc × (1mL HoAc/1.05g HoAc)= 1.30mL HoAc

20% HoAc Reaction Ratio:

  MW R-CH2CHOH-R: 44.00 g/mol
  MW Acetic Acid (HoAc): 60.00 g/mol
  1.0g PVOH × (1 mol PVOH/44.00g PVOH) × (0.2 mol HoAc/1 mol PVOH) × (60.00g HoAc/1 mol HoAc) = 0.27g HoAc
  0.27g HoAc × (1mL HoAc/1.05g HoAc)= 0.26mL HoAc

40% HoAc Reaction Ratio:

  MW R-CH2CHOH-R: 44.00 g/mol
  MW Acetic Acid (HoAc): 60.00 g/mol
  1.0g PVOH × (1 mol PVOH/44.00g PVOH) × (0.4 mol HoAc/1 mol PVOH) × (60.00g HoAc/1 mol HoAc) = 0.55g HoAc
  0.55g HoAc × (1mL HoAc/1.05g HoAc)= 0.52mL HoAc

60% HoAc Reaction Ratio:

  MW R-CH2CHOH-R: 44.00 g/mol
  MW Acetic Acid (HoAc): 60.00 g/mol
  1.0g PVOH × (1 mol PVOH/44.00g PVOH) × (0.6 mol HoAc/1 mol PVOH) × (60.00g HoAc/1 mol HoAc) = 0.82g HoAc
  0.82g HoAc × (1mL HoAc/1.05g HoAc)= 0.78mL HoAc