User:Allison K. Alix/Notebook/Thesis Research/2013/10/08: Difference between revisions
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average τ<sub>D</sub> = 36.3137ms = 0.0363137 sec (taken from 10000X beads on 9/4, 9/11, and 9/12) | average τ<sub>D</sub> = 36.3137ms = 0.0363137 sec (taken from 10000X beads on 9/4, 9/11, and 9/12) | ||
sqr rt [(0.0363137s)(4)(1.3806488 × 10-23 m<sup>2</sup> kg s<sup>-2</sup> | sqr rt [(0.0363137s)(4)(1.3806488 × 10-23 m<sup>2</sup> kg s<sup>-2</sup> K<sup>-1</sup>)(291.7K)]/[3(0.001028kg/m s)(pi)(2x10<sup>-7</sup>) = 5.49x10<sup>-7</sup> m = | ||
Revision as of 11:02, 8 October 2013
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<html><img src="/images/9/94/Report.png" border="0" /></html> Main project page <html><img src="/images/c/c3/Resultset_previous.png" border="0" /></html>Previous entry<html> </html>Next entry<html><img src="/images/5/5c/Resultset_next.png" border="0" /></html> |
CalculationsτD = (ω023ηπd)/4kT where τD is the diffusion time of the sample ω0 is the radius of the spot η is the viscosity of the solvent (water), 0.001028kg/m s d is the diameter of the particle k is Boltzmann's constant = 1.3806488 × 10-23 m2 kg s-2-2 K-1 T is the temperature of the room (18.7 °C, 291.7K) Calculating ω0 using 10000X diluted green fluorescent beadsaverage τD = 36.3137ms = 0.0363137 sec (taken from 10000X beads on 9/4, 9/11, and 9/12) sqr rt [(0.0363137s)(4)(1.3806488 × 10-23 m2 kg s-2 K-1)(291.7K)]/[3(0.001028kg/m s)(pi)(2x10-7) = 5.49x10-7 m =
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