Difference between revisions of "User:Allison K. Alix/Notebook/Thesis Research/2013/08/27"

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(Procedures)
(Addition of ThT)
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[ThT] must be twice what [DNA] is
 
[ThT] must be twice what [DNA] is
  
[DNA] = 1.11225μM, so [ThT] must be 2.2245μM
+
[DNA] = 0.624μM, so [ThT] must be 1.248μM
  
Use 250μL of DNA-AuNP solution (10%=25μM)
+
Use 150μL of DNA-AuNP solution (10%=15μL)
  
2.2245x10-6M x 275x10-6L solution = 6.117375x10-10 moles ThT
+
1.248x10-6M x 165x10-6L solution = 2.0592x10-10 moles ThT
  
(6.117375x10-10 moles ThT)/ 25 x 10-6 L = 24.4695μM
+
(2.0592x10-10 moles ThT)/ 15 x 10-6 L = 13.728μM
  
-Add 25μL of 24.4695μM ThT to 250μL thiol-DNA/AuNP solution
+
-Add 15μL of 13.728μM to 150μL thiol-DNA/AuNP solution
  
 
NEW Concentrations:
 
NEW Concentrations:
  
[DNA]= 1.011μM [AuNP] = 13.486μM [ThT] = 2.2245μM
+
[DNA]= 0.567μM, [ThT] = 1.248μM
  
 
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Revision as of 08:46, 27 August 2013

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To Do

  • Add Filter to FCS
  • Align using YG Fluorescent Beads
  • Add ThT to Au@SiO2/DNA solution
  • Obtain UV-Vis and Fluorescence of above solution

Au@SiO2/DNA UV-Vis Data

DNA method 2.jpg

ε of thiol-DNA= 607500 A=0.379 b=1 cm

A=εbc

c=A/εb

c = 6.23x10^-7M = 0.624uM

Addition of ThT

[ThT] must be twice what [DNA] is

[DNA] = 0.624μM, so [ThT] must be 1.248μM

Use 150μL of DNA-AuNP solution (10%=15μL)

1.248x10-6M x 165x10-6L solution = 2.0592x10-10 moles ThT

(2.0592x10-10 moles ThT)/ 15 x 10-6 L = 13.728μM

-Add 15μL of 13.728μM to 150μL thiol-DNA/AuNP solution

NEW Concentrations:

[DNA]= 0.567μM, [ThT] = 1.248μM