User:Allison K. Alix/Notebook/Thesis Research/2013/04/09: Difference between revisions
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WARNING: ethanethiol is very volatile. Handle under the hood only wearing PPE. | WARNING: ethanethiol is very volatile. Handle under the hood only wearing PPE. | ||
* original | * original concentration of AuNP = 19.4nM | ||
* desired concentration of ethanethiol = 19.4nM x(15393) = 298624.2nM = 298μM | * desired concentration of ethanethiol = 19.4nM x(15393) = 298624.2nM = 298μM | ||
* density of ethanethiol = 0.839g/mL | * density of ethanethiol = 0.839g/mL | ||
1) | 1) Find the concentration of 0.0125mL pure ethanethiol in 5mL water | ||
0.839g/mL x 0. | 0.839g/mL x 0.0125mL = 0.0104875g | ||
0.0104875g/(62.13 g/mol) = 1.68799 x 10<sup>-4</sup> mol | |||
1.68799 x 10<sup>-4</sup> mol/5mL x (1000mL/1L) = 0.034M = 34mM | |||
340mM (x) = (30mM)(1mL) | 340mM (x) = (30mM)(1mL) |
Revision as of 08:47, 9 April 2013
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Objectives
ProceduresPart 1: Preparation of 1mL of 2.98μM ethane thiol WARNING: ethanethiol is very volatile. Handle under the hood only wearing PPE.
1) Find the concentration of 0.0125mL pure ethanethiol in 5mL water 0.839g/mL x 0.0125mL = 0.0104875g 0.0104875g/(62.13 g/mol) = 1.68799 x 10-4 mol 1.68799 x 10-4 mol/5mL x (1000mL/1L) = 0.034M = 34mM
340mM (x) = (30mM)(1mL) x = 0.088mL = 88μL in 912μL H2O 30mM (x) = 3mM (1mL) x = 100μL in 900μL 3mM(x) = 298μM (1mL) x = 99μL in 901μL to obtain 298μM ethanethiol 2) Reacting AuNP with ethanethiol
Part 2: Measure absorbance/fluorescence of AuNP-MB Part 3: Measure absorbance/fluorescence of AuNP-ThT
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