Difference between revisions of "User:Allison K. Alix/Notebook/CHEM-581/2013/02/06"

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==Calculations==
 
==Calculations==
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'''Preparation of 20mM phosphate buffer, pH = 7.4'''
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[Base] = monosodium phosphate, 119.98 g/mol
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[Acid] = disodium phosphate, 141.96 g/mol
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pH = pKa + log ([Base]/[Acid])
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7.4 = 7.3 + log ([Base]/[Acid])
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([Base]/[Acid]) = 1.2589
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[Acid] + [Base] = 20mM
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[Base] = 20mM - [Acid]
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(20mM - [Acid])/[Acid] = 1.2589
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[disodium phosphate] = 8.85mM
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[monosodium phosphate] = 11.14mM
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8.85mmol x 141.96g/mol x 1mol/1000mmol = 1.256g disodium phosphate
  
 
==References==
 
==References==

Revision as of 07:35, 6 February 2013

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Objective

-Begin PVA microsphere preparation

Procedure

Preparation of 20mM phosphate buffer, pH = 7.4

[Base] = monosodium phosphate, 119.98 g/mol [Acid] = disodium phosphate, 141.96 g/mol

pH = pKa + log ([Base]/[Acid])

7.4 = 7.3 + log ([Base]/[Acid])

([Base]/[Acid]) = 1.2589

[Acid] + [Base] = 20mM

[Base] = 20mM - [Acid]

(20mM - [Acid])/[Acid] = 1.2589

[disodium phosphate] = 8.85mM

[monosodium phosphate] = 11.14mM

8.85mmol x 141.96g/mol x 1mol/1000mmol = 1.256g disodium phosphate

11.14mmol x 119.98g/mol x 1mol/1000mmol = 1.337g monosodium phosphate

Calculations

Preparation of 20mM phosphate buffer, pH = 7.4

[Base] = monosodium phosphate, 119.98 g/mol [Acid] = disodium phosphate, 141.96 g/mol

pH = pKa + log ([Base]/[Acid])

7.4 = 7.3 + log ([Base]/[Acid])

([Base]/[Acid]) = 1.2589

[Acid] + [Base] = 20mM

[Base] = 20mM - [Acid]

(20mM - [Acid])/[Acid] = 1.2589

[disodium phosphate] = 8.85mM

[monosodium phosphate] = 11.14mM

8.85mmol x 141.96g/mol x 1mol/1000mmol = 1.256g disodium phosphate

References

http://www.sciencedirect.com/science/article/pii/S0168365998000893


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