Difference between revisions of "User:Allison K. Alix/Notebook/CHEM-581/2012/10/26"

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<div class="center" style="width:auto; margin-left:auto; margin-right:auto;">Preparation of 50μM Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub></div>
 
<div class="center" style="width:auto; margin-left:auto; margin-right:auto;">Preparation of 50μM Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub></div>
  
<math>\frac {278.01 g} {mol} \times \frac {50 x 10^-3 mol} {L} \times \frac {1 L} {1000 mL} \times 10mL = 0.138 g in 10mL </math>
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<math>\frac {278.01 g} {mol} \times \frac {50 x 10^-3 mol} {L} \times \frac {1 L} {1000 mL} \times 10mL = 0.138 g</math>
  
 +
0.138 g Fe<sub>2</sub>(SO<sub>4</sub> in 10mL H<sub>2</sub>O to get 50mM. Dilute to 50μM by using 0.01 mL (10μL) in 9.99mL (9990μL) H<sub>2</sub>O
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[[Image:GraphImage.png‎]]
 
[[Image:GraphImage.png‎]]
  

Revision as of 12:29, 6 November 2012

BDLlogo notext lr.png Experimental Chemistry <html><img src="/images/9/94/Report.png" border="0" /></html> Main project page
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Objective

  • Take UV-Vis spectra of mixtures of previously prepared salt solutions and porphyrin solution in 1:1 ratio at the same concentrations (50micM)
  • Take IR spectra of films

Description

  1. Finish preparing the following sulfate solutions
    1. 10mL 50 μM H2SO4
    2. 10mL 50 μM Fe2(SO4)3
  2. Begin taking IR measurements of all films synthesized thus far

Data

Preparation of 50μM H2SO4

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://api.formulasearchengine.com/v1/":): {\displaystyle \frac {50 x 10^-3 mol} {L} \times \frac {98.07 g} {mol} \times 10mL \times \frac {1L} {1000 mL} \times \frac {1mL} {1.84 g} = 0.0266mL}

0.0266mL = 26.65μL


Preparation of 50μM Fe2(SO4)3

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://api.formulasearchengine.com/v1/":): {\displaystyle \frac {278.01 g} {mol} \times \frac {50 x 10^-3 mol} {L} \times \frac {1 L} {1000 mL} \times 10mL = 0.138 g}

0.138 g Fe2(SO4 in 10mL H2O to get 50mM. Dilute to 50μM by using 0.01 mL (10μL) in 9.99mL (9990μL) H2O


GraphImage.png

Notes

This area is for any observations or conclusions that you would like to note.


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