User:Allison K. Alix/Notebook/CHEM-581/2012/10/24: Difference between revisions

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==Data==
==Data==
<div class="center" style="width:auto; margin-left:auto; margin-right:auto;">Preparation of 50 μM Na<sub>2</sub>SO<sub>4</sub></div>
<math> \frac {142.07 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1 L} {1000mL} \times 10mL = 0.071035 g</math>
0.071035 g Na<sub>2</sub>SO<sub>4</sub> in 10mL H<sub>2</sub>O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H<sub>2</sub>O.
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<div class="center" style="width:auto; margin-left:auto; margin-right:auto;">Preparation of 50 μM 72 wt% Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub></div>
<math> \frac {72} {100} \times \frac {399.88 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1L} {1000mL} \times \frac 10mL = 0.144g </math>
0.144 g 72 wt% Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> in 10mL H<sub>2</sub>O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H<sub>2</sub>O.
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[[Image:GraphPorphyrinSolutions.png]]
[[Image:GraphPorphyrinSolutions.png]]


Revision as of 14:12, 6 November 2012

Experimental Chemistry <html><img src="/images/9/94/Report.png" border="0" /></html> Main project page
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Objective

  • Take UV-Vis of porphyrin solutions
  • Re-do crosslinking of porphyrin films
  • Prepare sulfate solutions

Description

  1. UV-Vis Spectra of porphyrin solutions with the following concentrations were collected:
    1. 25μM
    2. 12.5μM
    3. 6.75μM
    4. 3.375μM
    5. 1.6875μM
  2. 10 mL 50 μM of the following sulfate solutions were prepared:
    1. Na2SO4
    2. Fe2(SO4)3
    3. Al2(SO4)3

Data

Preparation of 50 μM Na2SO4

[math]\displaystyle{ \frac {142.07 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1 L} {1000mL} \times 10mL = 0.071035 g }[/math]

0.071035 g Na2SO4 in 10mL H2O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H2O.

Preparation of 50 μM 72 wt% Fe2(SO4)3

[math]\displaystyle{ \frac {72} {100} \times \frac {399.88 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1L} {1000mL} \times \frac 10mL = 0.144g }[/math]

0.144 g 72 wt% Fe2(SO4)3 in 10mL H2O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H2O.


Notes

This area is for any observations or conclusions that you would like to note.


Use categories like tags. Change the "Course" category to the one corresponding to your course. The "Miscellaneous" tag can be used for particular experiments, as instructed by your professor. Please be sure to change or delete this tag as required so that the categories remain well organized.



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