Todd:Chem3x11 ToddL6

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Chem3x11 Lecture 6

Essentially Done, Sat May 12.

This lecture is about the SN2' Mechanism and we will look at some past papers.

(Back to the main teaching page)

Key concepts

  • When a leaving group is adjacent to a double bond, there is an alternative substitution reaction mechanism available

Allylic Substitution

The allylic position is the one next to a double bond, not on it (which is the vinylic position). Substitution there by an SN2 mechanism is fast - much faster than the corresponding alkyl compound.

Scheme 1: Allylic Substitution is Fast

We're not meant to be talking about this, but the reason the substitution is faster at an allylic position is interesting. The effect is quite dramatic - allylic substitution is typically 100 x faster than substitution on an alkyl ("aliphatic") chain. The fact that the reaction is faster implies that the transition state is being stabilised by the adjacent π bond of the double bond. The transition state of an SN2 reaction has two partial bonds - one from the incoming nucleophile and one from the leaving group. These two partial bonds "derived from mixing a filled and a vacant orbital can be regarded as having to some extent the character of both. This means that stabilising delocalisation should be available from both electron donor and vacant orbitals" as Tony Kirby puts it very eloquently in Stereoelectronic Effects (section 5.3).

Scheme 2: Adjacent Π Stabilises SN2 Transition State

The same kind of thing happens at benzylic centres. According to Kirby's idea, both electron withdrawing and donating substituents on the aromatic ring should accelerate benzylic displacements, and this is actually the case. Very cool. Interestingly displacements next to carbonyl groups are also accelerated, but in those cases it's the carbonyl π* that's interacting with the transition state. Anyway, you don't need to know this.

The SN2' Mechanism

We need to return to the allylic substitution. There will be times when the regular SN2 displacement does not happen, for example when SN1 might be favoured (if the reaction is in a polar solvent which is good at stabilising the cation). But imagine we're in a non-polar solvent and we have a starting material where the regular displacement site (where the leaving group is attached) is sterically congested. It turns out you can easily get displacement through attack of the nucleophile at the end of the double bond. This is the SN2' (say "SN2 prime") mechanism that you need to know and deploy at appropriate moments.

Scheme 3: The SN2' Mechanism

Stereochemistry of the SN2' Reaction in Cyclic Systems

Cyclohexenes are quite common, and you need to be able to draw mechanisms involving such structures. If we examine SN2' reactions in cyclic cases it turns out that the reactions proceed either with the incoming nucleophile from the same face of the ring that the leaving group was on (syn) or from the opposite side (anti). So in any given case, we get a major and a minor product, but which we get varies depending on the leaving group and nucleophile. Here's an example where the outcome changes depending on the nucleophile.

Scheme 4: Syn vs Anti products in the SN2' Reaction of Cyclohexenes

You might think that the outcome would depend on the chair/boat/ringflip issues we originally went through with cyclohexanes. Well, in cyclohexenes, the ring, while locked by that bulky substituent, is quite flat around the double bond and we don't have a great deal of difference between the two faces of the double bond. So there isn't a clear reason why one approach should be favoured in any given instance - it's not very well understood (unless someone knows better).

Scheme 5: Nucleophile Approach to the Cyclohexene Double Bond

Take a look at the way these are drawn, and how the bulky substituent is equatorial in the starting material, and "pseudoequatorial" in the product. We'll come back to drawings like this. There are other cases where the approach direction really matters.

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Is CC-BY-3.0 meaning you can use whatever you want, provided you cite me.