Difference between revisions of "IGEM:American University/2009/Notebook/Advanced Experimental Chemistry: Fun Times in Beeghly/2013/03/08"

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(Welcome to Advanced Experimental Chemistry)
(Today's Procedure)
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Same procedure as 2/15: Preparing PVOH and 3-Chloro-2-Hydroxypropyltrimethylammonium chloride reacted crystals.
 
Same procedure as 2/15: Preparing PVOH and 3-Chloro-2-Hydroxypropyltrimethylammonium chloride reacted crystals.
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4 sets of 2g PVOH were left to dissolve (as much as possible on a stir plate) in 5mL 0.2M NaOH for 30 minutes. 0.855g of 3-Chloro-2-Hydroxypropyltrimethylammonium chloride was left to dissolve in 5mL 0.2M NaOH for 30 minutes.
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0.01%: x/0.855g=0.01%/10%, x=0.000855g. 0.000855g/0.171(g/mL)= 0.005mL of the "stock" 3-Chloro-2-Hydroxypropyltrimethylammonium chloride solution. Thus to make our
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0.01% 3-Chloro-2-Hydroxypropyltrimethylammonium chloride:PVOH, would require the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.005mL of the "stock" 3-Chloro-2-Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.995mL extra NaOH 0.2M]. Similarly...
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0.1%: Required the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.05mL of the "stock" 3-Chloro-2-Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.95mL extra NaOH].
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1%: Require the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.5mL of the "stock" 3-Chloro-2-Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.5mL extra NaOH].
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To make the "10%" solution, we used the 4.445mL left over "10% stock" 3-Chloro-2-Hydroxypropyltrimethylammonium chloride solution. To solve for the actual percentage this makes... (4.445mL)(0.171g/mL 3-Chloro-2-Hydroxypropyltrimethylammonium chloride) = 0.760095g 3-Chloro-2-Hydroxypropyltrimethylammonium chloride (0.760095g)/(0.855g)=x%/10% x=8.89% so, the solution is actually 8.89% of PVOH OH groups reacting w 3-Chloro-2-Hydroxypropyltrimethylammonium chloride.
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Revision as of 10:34, 8 March 2013

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Welcome to Advanced Experimental Chemistry

Today's Procedure

Same procedure as 2/15: Preparing PVOH and 3-Chloro-2-Hydroxypropyltrimethylammonium chloride reacted crystals.

4 sets of 2g PVOH were left to dissolve (as much as possible on a stir plate) in 5mL 0.2M NaOH for 30 minutes. 0.855g of 3-Chloro-2-Hydroxypropyltrimethylammonium chloride was left to dissolve in 5mL 0.2M NaOH for 30 minutes.

0.01%: x/0.855g=0.01%/10%, x=0.000855g. 0.000855g/0.171(g/mL)= 0.005mL of the "stock" 3-Chloro-2-Hydroxypropyltrimethylammonium chloride solution. Thus to make our 0.01% 3-Chloro-2-Hydroxypropyltrimethylammonium chloride:PVOH, would require the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.005mL of the "stock" 3-Chloro-2-Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.995mL extra NaOH 0.2M]. Similarly...

0.1%: Required the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.05mL of the "stock" 3-Chloro-2-Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.95mL extra NaOH].

1%: Require the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.5mL of the "stock" 3-Chloro-2-Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.5mL extra NaOH].

To make the "10%" solution, we used the 4.445mL left over "10% stock" 3-Chloro-2-Hydroxypropyltrimethylammonium chloride solution. To solve for the actual percentage this makes... (4.445mL)(0.171g/mL 3-Chloro-2-Hydroxypropyltrimethylammonium chloride) = 0.760095g 3-Chloro-2-Hydroxypropyltrimethylammonium chloride (0.760095g)/(0.855g)=x%/10% x=8.89% so, the solution is actually 8.89% of PVOH OH groups reacting w 3-Chloro-2-Hydroxypropyltrimethylammonium chloride.