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Threshold in Hodgkin-Huxley model

  • threshold is sharp
  • change in [math]10^{-8}-10^{-14}[/math] can change AP to non-AP in model
  • determine threshold in model
  • asssume n & h are so slow that [math]n(V_m,t)=n_\infty(V_m^o)[/math] and [math]h(V_m,t)=h_\infty(V_m^o)[/math]
  • Also m is so fast that [math]m(V_m,t)=m_\infty(V_m)[/math]
  • The potassium current is constant as the the potassium conductance doesn't change
  • Find that there are 2 stable equilibrium points and 1 unstable point
  • The unstable point is the threshold voltage
  • We can relax assumption that m is instant and instead obeys the standard HH model for m
  • Make phase plane showing m vs [math]V_m[/math]
  • To be at equilibrium, must be on isoclines
    • [math]\frac{dm}{dt} = 0 \rightarrow m=m_\infty[/math]
    • [math]\frac{V_m}{dt} = 0[/math]
    • These two lines again cross 3 times, with one point being unstable
  • The separatrix curve in [math]m-V_m[/math] space determines whether will go to rest or [math]V_{Na}[/math]
  • So threshold depends on both m and [math]V_m[/math]
  • If instead of fixing h to [math]h_\infty[/math], we set it to another value, as h decreases, the isoclines change such that thresholds increase until a point when the curves only intersect once at rest
    • This explains the relative and absolute refractory period
    • The relative refractory period is characterized by higher threshold
    • During the absolute refractory period it is impossible to reach threshold no matter the amount of stimulus