BME100 s2015:Group4 12pmL2

BME 100 Spring 2015	Home People Lab Write-Up 1 | Lab Write-Up 2 | Lab Write-Up 3 Lab Write-Up 4 | Lab Write-Up 5 | Lab Write-Up 6 Course Logistics For Instructors Photos Wiki Editing Help
OUR TEAM Name: Nima Sadeghi Name: Sydney Wallace Name: Your name Name: Your name Name: Your name LAB 2 WRITE-UP Descriptive Statistics Experiment 1 The average of the data set for an LPS Dose of 0mg was 10.516. The average of the data set for an LPS Dose of 10mg was 11.112. For standard deviation, the LPS Dose of 0mg had a standard deviation of 2.225 whereas the standard deviation of the LPS Dose of 10mg had a standard deviation of 7.403. There were five data points of 0mg LPS Dose and five data points of 10mg LPS Dose. The standard error for 0mg LPS Dose was 0.995 and the standard error for 10mg LPS Dose was 2.236. The T-test results for the first experiment was 0.867. Experiment 2 The average of the data set for an LPS Dose of 0mg was 3.834, the average for 5mg was 8.932, the average for 10mg was 61.622, and the average for 15mg was 657.941. The standard deviations for the LPS Doses 0mg-15mg were 1.523, 1.5939, 30.111, and 213.943 respectively. There were 10 data points for all four doses of LPS. The standard error was 0.482 for 0mg LPS dose, 0.504 for 5mg LPS dose, 9.522 for 10mg LPS dose, and 67.338 for 15mg LPS dose. The anova test showed a p-value of 1.4E-16 which is below the 0.05 alpha value. The bonferroni correction shows that all of the data sets are significant. Results Experiment 1 The data shows that on average, taking into account the standard deviation, an increase in dosage of LPS in rats does not affect the inflammotin in the rats. ‎Experiment 2 The data shows that on average, taking into account the standard deviation, an increase in dosage of LPS in rats causes an exponential growth in the inflammotin in the patients. Analysis Experiment 1 Experiment 2 Summary/Discussion