User:Tyler Wynkoop/Tyler's Page/eDiffraction: Difference between revisions
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According to our data the d-spacing of the crystal lattice is d = .195E-9 ± 1E-12 nm and d = .114E-9 ± 0.4E-12 nm. The accepted values are d = 0.213*10^-9 nm and d = 0.213*10^-9 nm, resulting in an 8% and 7% error respectively. Dan was able to develop a graph of error, here. | According to our data the d-spacing of the crystal lattice is d = .195E-9 ± 1E-12 nm and d = .114E-9 ± 0.4E-12 nm. The accepted values are d = 0.213*10^-9 nm and d = 0.213*10^-9 nm, resulting in an 8% and 7% error respectively. Dan was able to develop a graph of error, here. {{SJK Comment|l=01:39, 22 December 2010 (EST)|c=As with the Millikan lab, it's not clear you did the analysis yourself as well?}} | ||
[[Image:DiametervsVoltage.jpg|thumb|left|Diameter vs 1/sqrt(kV)]] | [[Image:DiametervsVoltage.jpg|thumb|left|Diameter vs 1/sqrt(kV)]] |
Latest revision as of 23:39, 21 December 2010
Electron Diffraction
In 1929, Louis De Broglie won the Nobel prize for his research in the wave-particle duality of matter. He developed the famous De Broglie hypothesis in which he uses Einstein's λ=cν in analysis of matter. He developed the equation:
[math]\displaystyle{ \lambda = \frac{h}{p} }[/math]
The Lab
In this lab we used a diffraction grating of graphite to produce visible results on a screen, via an electron beam. The crystal lattice of the graphite is known to have two characteristic spacings in which electrons are diffracted through. These two spacings produce two rings in the electron beam on the screen. By measuring the voltage propelling the electrons and the diameter of the rings, we can measure the wavelengths of the electrons.
Data
According to our data the d-spacing of the crystal lattice is d = .195E-9 ± 1E-12 nm and d = .114E-9 ± 0.4E-12 nm. The accepted values are d = 0.213*10^-9 nm and d = 0.213*10^-9 nm, resulting in an 8% and 7% error respectively. Dan was able to develop a graph of error, here. SJK 01:39, 22 December 2010 (EST)
Using the Bragg condition
[math]\displaystyle{ 2\cdot d\cdot sin \theta = 2 \cdot d \theta = n \lambda \,\! }[/math]
Simplifying for small angles, and remembering that the angle of diffraction is 2θ, the relationship becomes
[math]\displaystyle{ \frac{R \cdot d}{L}=\lambda }[/math]
where
- R = .066 meters
- L = .13 meters
This yields
- λ = 9.900E-11±1.02E-13
- λ = 5.788E-11±4.06E-13
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