# User:Timothee Flutre/Notebook/Postdoc/2011/12/14

(Difference between revisions)
 Revision as of 11:29, 4 January 2012 (view source) (→Learn about mixture models and the EM algorithm: add constraints mix weights)← Previous diff Revision as of 13:41, 4 January 2012 (view source) (→Learn about mixture models and the EM algorithm: rewrite comp lik)Next diff → Line 27: Line 27: $p(k/i) = P(Z_i=k/x_i,\theta) = \frac{w_k g(x_i/\mu_k,\sigma_k)}{\sum_{l=1}^K w_l g(x_i/\mu_l,\sigma_l)}$ $p(k/i) = P(Z_i=k/x_i,\theta) = \frac{w_k g(x_i/\mu_k,\sigma_k)}{\sum_{l=1}^K w_l g(x_i/\mu_l,\sigma_l)}$ - We can now write the complete likelihood, ie. the likelihood of the augmented model (even if we don't need it in the following), where $I_k = \{i / Z_i = k\}$: + We can now write the complete likelihood, ie. the likelihood of the augmented model, assuming all observations are independent: - $L_{comp}(\theta) = P(X,Z/\theta) = P(X/Z,\theta) P(Z/\theta) = \left( \prod_{k=1}^K \prod_{i \in I_k} g(x_i/\mu_k,\sigma_k) \right) \prod_{i=1}^N P(Z_i/\theta)$. + $L_{comp}(\theta) = P(X,Z/\theta) = P(X/Z,\theta) P(Z/\theta) = \left( \prod_{i=1}^N \sum_{k=1}^K \mathbf{1}_{\{z_i=k\}} g(x_i/\mu_k,\sigma_k) \right) \prod_{i=1}^N P(Z_i/\theta)$. - And, more useful, the incomplete (or marginal) likelihood, assuming all observations are independent: + And also the incomplete (or marginal) likelihood: $L_{incomp}(\theta) = P(X/\theta) = \prod_{i=1}^N f(x_i/\theta)$ $L_{incomp}(\theta) = P(X/\theta) = \prod_{i=1}^N f(x_i/\theta)$ * '''ML estimation''': we want to find the values of the parameters that maximize the likelihood. This reduces to (i) differentiating the log-likelihood with respect to each parameter, and then (ii) finding the value at which each partial derivative is zero. Instead of maximizing the likelihood, we maximize its logarithm, noted $l(\theta)$. It gives the same solution because the log is monotonically increasing, but it's easier to derive the log-likelihood than the likelihood. Here is the whole formula for the (incomplete) log-likelihood: * '''ML estimation''': we want to find the values of the parameters that maximize the likelihood. This reduces to (i) differentiating the log-likelihood with respect to each parameter, and then (ii) finding the value at which each partial derivative is zero. Instead of maximizing the likelihood, we maximize its logarithm, noted $l(\theta)$. It gives the same solution because the log is monotonically increasing, but it's easier to derive the log-likelihood than the likelihood. Here is the whole formula for the (incomplete) log-likelihood: - $l(\theta) = \sum_{i=1}^N log(f(x_i/\theta)) = \sum_{i=1}^N log \left( \sum_{k=1}^{K} w_k \frac{1}{\sqrt{2\pi} \sigma_k} \exp^{-\frac{1}{2}(\frac{x_i - \mu_k}{\sigma_k})^2} \right)$ + $l(\theta) = log(L_{incomp}(\theta)) = \sum_{i=1}^N log(f(x_i/\theta)) = \sum_{i=1}^N log \left( \sum_{k=1}^{K} w_k \frac{1}{\sqrt{2\pi} \sigma_k} \exp \left( -\frac{1}{2}(\frac{x_i - \mu_k}{\sigma_k})^2 \right) \right)$ - * '''MLE analytical formulae''': a few important rules are required, but only from a high-school level in maths (see [http://en.wikipedia.org/wiki/Differentiation_%28mathematics%29#Rules_for_finding_the_derivative here]). Let's start by finding the maximum-likelihood estimates of the mean of each cluster: + * '''MLE analytical formulae''': a few important rules are required to write down the analytical formulae of the MLEs, but only from a high-school level (see [http://en.wikipedia.org/wiki/Differentiation_%28mathematics%29#Rules_for_finding_the_derivative here]). Let's start by finding the maximum-likelihood estimates of the mean of each cluster: $\frac{\partial l(\theta)}{\partial \mu_k} = \sum_{i=1}^N \frac{1}{f(x_i/\theta)} \frac{\partial f(x_i/\theta)}{\partial \mu_k}$ $\frac{\partial l(\theta)}{\partial \mu_k} = \sum_{i=1}^N \frac{1}{f(x_i/\theta)} \frac{\partial f(x_i/\theta)}{\partial \mu_k}$

## Revision as of 13:41, 4 January 2012

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## Learn about mixture models and the EM algorithm

(Caution, this is my own quick-and-dirty tutorial, see the references at the end for presentations by professional statisticians.)

• Motivation: a large part of any scientific activity is about measuring things, in other words collecting data, and it is not infrequent to collect heterogeneous data. For instance, we measure the height of individuals without recording their gender, we measure the levels of expression of a gene in several individuals without recording which ones are healthy and which ones are sick, etc. It seems therefore natural to say that the samples come from a mixture of clusters. The aim is then to recover from the data, ie. to infer, (i) the values of the parameters of the probability distribution of each cluster, and (ii) from which cluster each sample comes from.
• Data: we have N observations, noted X = (x1,x2,...,xN). For the moment, we suppose that each observation xi is univariate, ie. each corresponds to only one number.
• Hypothesis: let's assume that the data are heterogeneous and that they can be partitioned into K clusters (see examples above). This means that we expect a subset of the observations to come from cluster k = 1, another subset to come from cluster k = 2, and so on.
• Model: technically, we say that the observations were generated according to a density function f. More precisely, this density is itself a mixture of densities, one per cluster. In our case, we will assume that each cluster k corresponds to a Normal distribution, which density is here noted g, with mean μk and standard deviation σk. Moreover, as we don't know for sure from which cluster a given observation comes from, we define the mixture weight wk to be the probability that any given observation comes from cluster k. As a result, we have the following list of parameters: θ = (w1,...,wK1,...μK1,...,σK). Finally, for a given observation xi, we can write the model:

$f(x_i/\theta) = \sum_{k=1}^{K} w_k g(x_i/\mu_k,\sigma_k) = \sum_{k=1}^{K} w_k \frac{1}{\sqrt{2\pi} \sigma_k} \exp \left(-\frac{1}{2}(\frac{x_i - \mu_k}{\sigma_k})^2 \right)$

The constraints are: $\forall k, w_k > 0$ and $\sum_{k=1}^K w_k = 1$

• Missing data: it is worth noting that a big piece of information is lacking here. We aim at finding the parameters defining the mixture, but we don't know from which cluster each observation is coming! That's why we need to introduce the following N latent variables Z1,...,Zi,...,ZN, one for each observation, such that Zi = k means that observation xi belongs to cluster k (indicators). This is called the "missing data formulation" of the mixture model. Thanks to this, we can reinterpret the mixture weights: wk = P(Zi = k / θ). Moreover, we can now define the membership probabilities, one for each observation:

$p(k/i) = P(Z_i=k/x_i,\theta) = \frac{w_k g(x_i/\mu_k,\sigma_k)}{\sum_{l=1}^K w_l g(x_i/\mu_l,\sigma_l)}$

We can now write the complete likelihood, ie. the likelihood of the augmented model, assuming all observations are independent: $L_{comp}(\theta) = P(X,Z/\theta) = P(X/Z,\theta) P(Z/\theta) = \left( \prod_{i=1}^N \sum_{k=1}^K \mathbf{1}_{\{z_i=k\}} g(x_i/\mu_k,\sigma_k) \right) \prod_{i=1}^N P(Z_i/\theta)$.

And also the incomplete (or marginal) likelihood:

$L_{incomp}(\theta) = P(X/\theta) = \prod_{i=1}^N f(x_i/\theta)$

• ML estimation: we want to find the values of the parameters that maximize the likelihood. This reduces to (i) differentiating the log-likelihood with respect to each parameter, and then (ii) finding the value at which each partial derivative is zero. Instead of maximizing the likelihood, we maximize its logarithm, noted l(θ). It gives the same solution because the log is monotonically increasing, but it's easier to derive the log-likelihood than the likelihood. Here is the whole formula for the (incomplete) log-likelihood:

$l(\theta) = log(L_{incomp}(\theta)) = \sum_{i=1}^N log(f(x_i/\theta)) = \sum_{i=1}^N log \left( \sum_{k=1}^{K} w_k \frac{1}{\sqrt{2\pi} \sigma_k} \exp \left( -\frac{1}{2}(\frac{x_i - \mu_k}{\sigma_k})^2 \right) \right)$

• MLE analytical formulae: a few important rules are required to write down the analytical formulae of the MLEs, but only from a high-school level (see here). Let's start by finding the maximum-likelihood estimates of the mean of each cluster:

$\frac{\partial l(\theta)}{\partial \mu_k} = \sum_{i=1}^N \frac{1}{f(x_i/\theta)} \frac{\partial f(x_i/\theta)}{\partial \mu_k}$

As we derive with respect to μk, all the others means μl with $l \ne k$ are constant, and thus disappear:

$\frac{\partial f(x_i/\theta)}{\partial \mu_k} = w_k \frac{\partial g(x_i/\mu_k,\sigma_k)}{\partial \mu_k}$

And finally:

$\frac{\partial g(x_i/\mu_k,\sigma_k)}{\partial \mu_k} = \frac{\mu_k - x_i}{\sigma_k^2} g(x_i/\mu_k,\sigma_k)$

Once we put all together, we end up with:

$\frac{\partial l(\theta)}{\partial \mu_k} = \sum_{i=1}^N \frac{1}{\sigma^2} \frac{w_k g(x_i/\mu_k,\sigma_k)}{\sum_{l=1}^K w_l g(x_i/\mu_l,\sigma_l)} (\mu_k - x_i) = \sum_{i=1}^N \frac{1}{\sigma^2} p(k/i) (\mu_k - x_i)$

By convention, we note $\hat{\mu_k}$ the maximum-likelihood estimate of μk:

$\frac{\partial l(\theta)}{\partial \mu_k}_{\mu_k=\hat{\mu_k}} = 0$

Therefore, we finally obtain:

$\hat{\mu_k} = \frac{\sum_{i=1}^N p(k/i) x_i}{\sum_{i=1}^N p(k/i)}$

By doing the same kind of algebra, we derive the log-likelihood w.r.t. σk:

$\frac{\partial l(\theta)}{\partial \sigma_k} = \sum_{i=1}^N p(k/i) (\frac{-1}{\sigma_k} + \frac{(x_i - \mu_k)^2}{\sigma_k^3})$

And then we obtain the ML estimates for the standard deviation of each cluster:

$\hat{\sigma_k} = \sqrt{\frac{\sum_{i=1}^N p(k/i) (x_i - \mu_k)^2}{\sum_{i=1}^N p(k/i)}}$

The partial derivative of l(θ) w.r.t. wk is tricky. ... <TO DO> ...

$\frac{\partial l(\theta)}{\partial w_k} = \sum_{i=1}^N (p(k/i) - w_k)$

Finally, here are the ML estimates for the mixture weights:

$\hat{w}_k = \frac{1}{N} \sum_{i=1}^N p(k/i)$

• EM algorithm: ... <TO DO> ...
• R code to simulate data:
#' Generate univariate observations from a mixture of Normals
#'
#' @param K number of components
#' @param N number of observations
#' @param gap difference between all component means
GetUnivariateSimulatedData <- function(K=2, N=100, gap=6){
mus <- seq(0, gap*(K-1), gap)
sigmas <- runif(n=K, min=0.5, max=1.5)
tmp <- floor(rnorm(n=K-1, mean=floor(N/K), sd=5))
ns <- c(tmp, N - sum(tmp))
clusters <- as.factor(matrix(unlist(lapply(1:K, function(k){rep(k, ns[k])})),
ncol=1))
obs <- matrix(unlist(lapply(1:K, function(k){
rnorm(n=ns[k], mean=mus[k], sd=sigmas[k])
})))
new.order <- sample(1:N, N)
obs <- obs[new.order]
rownames(obs) <- NULL
clusters <- clusters[new.order]
return(list(obs=obs, clusters=clusters, mus=mus, sigmas=sigmas,
mix.weights=ns/N))
}

• R code for the E step:
#' Return probas of latent variables given data and parameters from previous iteration
#'
#' @param data Nx1 vector of observations
#' @param params list which components are mus, sigmas and mix.weights
Estep <- function(data, params){
GetMembershipProbas(data, params$mus, params$sigmas, params$mix.weights) }  #' Return the membership probabilities P(zi=k/xi,theta) #' #' @param data Nx1 vector of observations #' @param mus Kx1 vector of means #' @param sigmas Kx1 vector of std deviations #' @param mix.weights Kx1 vector of mixture weights w_k=P(zi=k/theta) #' @return NxK matrix of membership probas GetMembershipProbas <- function(data, mus, sigmas, mix.weights){ N <- length(data) K <- length(mus) tmp <- matrix(unlist(lapply(1:N, function(i){ x <- data[i] norm.const <- sum(unlist(Map(function(mu, sigma, mix.weight){ mix.weight * GetUnivariateNormalDensity(x, mu, sigma)}, mus, sigmas, mix.weights))) unlist(Map(function(mu, sigma, mix.weight){ mix.weight * GetUnivariateNormalDensity(x, mu, sigma) / norm.const }, mus[-K], sigmas[-K], mix.weights[-K])) })), ncol=K-1, byrow=TRUE) membership.probas <- cbind(tmp, apply(tmp, 1, function(x){1 - sum(x)})) names(membership.probas) <- NULL return(membership.probas) }  #' Univariate Normal density GetUnivariateNormalDensity <- function(x, mu, sigma){ return( 1/(sigma * sqrt(2*pi)) * exp(-1/(2*sigma^2)*(x-mu)^2) ) }  • R code for the M step: #' Return ML estimates of parameters #' #' @param data Nx1 vector of observations #' @param params list which components are mus, sigmas and mix.weights #' @param membership.probas NxK matrix with entry i,k being P(zi=k/xi,theta) Mstep <- function(data, params, membership.probas){ params.new <- list() sum.membership.probas <- apply(membership.probas, 2, sum) params.new$mus <- GetMlEstimMeans(data, membership.probas,
sum.membership.probas)
params.new$sigmas <- GetMlEstimStdDevs(data, params.new$mus,
membership.probas,
sum.membership.probas)
params.new$mix.weights <- GetMlEstimMixWeights(data, membership.probas, sum.membership.probas) return(params.new) }  #' Return ML estimates of the means (1 per cluster) #' #' @param data Nx1 vector of observations #' @param membership.probas NxK matrix with entry i,k being P(zi=k/xi,theta) #' @param sum.membership.probas Kx1 vector of sum per column of matrix above #' @return Kx1 vector of means GetMlEstimMeans <- function(data, membership.probas, sum.membership.probas){ K <- ncol(membership.probas) sapply(1:K, function(k){ sum(unlist(Map("*", membership.probas[,k], data))) / sum.membership.probas[k] }) }  #' Return ML estimates of the std deviations (1 per cluster) #' #' @param data Nx1 vector of observations #' @param membership.probas NxK matrix with entry i,k being P(zi=k/xi,theta) #' @param sum.membership.probas Kx1 vector of sum per column of matrix above #' @return Kx1 vector of std deviations GetMlEstimStdDevs <- function(data, means, membership.probas, sum.membership.probas){ K <- ncol(membership.probas) sapply(1:K, function(k){ sqrt(sum(unlist(Map(function(p_ki, x_i){ p_ki * (x_i - means[k])^2 }, membership.probas[,k], data))) / sum.membership.probas[k]) }) }  #' Return ML estimates of the mixture weights #' #' @param data Nx1 vector of observations #' @param membership.probas NxK matrix with entry i,k being P(zi=k/xi,theta) #' @param sum.membership.probas Kx1 vector of sum per column of matrix above #' @return Kx1 vector of mixture weights GetMlEstimMixWeights <- function(data, membership.probas, sum.membership.probas){ K <- ncol(membership.probas) sapply(1:K, function(k){ 1/length(data) * sum.membership.probas[k] }) }  • R code for the EM loop: ... <TO DO> ... • Example: and now, let's try it! ## simulate data K <- 3 N <- 300 simul <- GetUnivariateSimulatedData(K, N) data <- simul$obs

## run the EM algorithm
params0 <- list(mus=runif(n=K, min=min(data), max=max(data)),
sigmas=rep(1, K),
mix.weights=rep(1/K, K))
res <- EMalgo(data, params0, 10^(-3), 1000, 1)

## check its convergence
plot(res$logliks, xlab="iterations", ylab="log-likelihood", main="Convergence of the EM algorithm", type="b")  ## plot the data along with the inferred densities png("mixture_univar_em.png") hist(data, breaks=30, freq=FALSE, col="grey", border="white", ylim=c(0,0.15), main="Histogram of data overlaid with densities inferred by EM") rx <- seq(from=min(data), to=max(data), by=0.1) ds <- lapply(1:K, function(k){dnorm(x=rx, mean=res$params$mus[k], sd=res$params$sigmas[k])}) f <- sapply(1:length(rx), function(i){ res$params$mix.weights[1] * ds[[1]][i] + res$params$mix.weights[2] * ds[[2]][i] + res$params$mix.weights[3] * ds[[3]][i] }) lines(rx, f, col="red", lwd=2) dev.off()  It seems to work well, which was expected as the clusters are well separated from each other... The classification of each observation can be obtained via the following command: ## get the classification of the observations memberships <- apply(res$membership.probas, 1, function(x){which(x > 0.5)})
table(memberships)

• References:
• introduction (ch.1) of the PhD thesis from Matthew Stephens (Oxford, 2000)
• tutorial from Carlo Tomasi (Duke University)
• book "Introducing Monte Carlo Methods with R" from Robert and and Casella (2009)