User:Timothee Flutre/Notebook/Postdoc/2011/12/14: Difference between revisions
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return( 1/(sigma * sqrt(2*pi)) * exp(-1/(2*sigma^2)*(x-mu)^2) ) | return( 1/(sigma * sqrt(2*pi)) * exp(-1/(2*sigma^2)*(x-mu)^2) ) | ||
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* '''References''': Diebolt and Robert (1994), Richardson and Green (1997), Stephens (PhD thesis, 2000) | |||
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Revision as of 09:50, 29 December 2011
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Learn about mixture models and the EM algorithm(Caution, this is my own quick-and-dirty tutorial, see the references at the end for presentations by professional statisticians.)
[math]\displaystyle{ l(\theta) = \sum_{i=1}^N log(f(x_i/\theta)) = \sum_{i=1}^N log( \sum_{k=1}^{K} w_k \frac{1}{\sqrt{2\pi} \sigma_k} \exp^{-\frac{1}{2}(\frac{x_i - \mu_k}{\sigma_k})^2}) }[/math]
[math]\displaystyle{ \frac{\partial l(\theta)}{\partial \mu_k} = \sum_{i=1}^N \frac{1}{f(x_i/\theta)} \frac{\partial f(x_i/\theta)}{\partial \mu_k} }[/math] As we derive with respect to [math]\displaystyle{ \mu_k }[/math], all the others means [math]\displaystyle{ \mu_l }[/math] with [math]\displaystyle{ l \ne k }[/math] are constant, and thus disappear: [math]\displaystyle{ \frac{\partial f(x_i/\theta)}{\partial \mu_k} = w_k \frac{\partial g(x_i/\mu_k,\sigma_k)}{\partial \mu_k} }[/math] And finally: [math]\displaystyle{ \frac{\partial g(x_i/\mu_k,\sigma_k)}{\partial \mu_k} = \frac{\mu_k - x_i}{\sigma_k^2} g(x_i/\mu_k,\sigma_k) }[/math] Once we put all together, we end up with: [math]\displaystyle{ \frac{\partial l(\theta)}{\partial \mu_k} = \sum_{i=1}^N \frac{1}{\sigma^2} \frac{w_k g(x_i/\mu_k,\sigma_k)}{\sum_{l=1}^K w_l g(x_i/\mu_l,\sigma_l)} (\mu_k - x_i) = \sum_{i=1}^N \frac{1}{\sigma^2} p(k/i) (\mu_k - x_i) }[/math] By convention, we note [math]\displaystyle{ \hat{\mu_k} }[/math] the maximum-likelihood estimate of [math]\displaystyle{ \mu_k }[/math]: [math]\displaystyle{ \frac{\partial l(\theta)}{\partial \mu_k}_{\mu_k=\hat{\mu_k}} = 0 }[/math] Therefore, we finally obtain: [math]\displaystyle{ \hat{\mu_k} = \frac{\sum_{i=1}^N p(k/i) x_i}{\sum_{i=1}^N p(k/i)} }[/math] By doing the same kind of algebra, we also obtain the ML estimates for the standard deviation of each cluster: [math]\displaystyle{ \hat{\sigma_k} = \sqrt{\frac{\sum_{i=1}^N p(k/i) (x_i - \mu_k)^2}{\sum_{i=1}^N p(k/i)}} }[/math]
#' Generate univariate observations from a mixture of Normals #' #' @param K number of components #' @param N number of observations GetUnivariateSimulatedData <- function(K=2, N=100){ mus <- seq(0, 6*(K-1), 6) sigmas <- runif(n=K, min=0.5, max=1.5) tmp <- floor(rnorm(n=K-1, mean=floor(N/K), sd=5)) ns <- c(tmp, N - sum(tmp)) clusters <- as.factor(matrix(unlist(lapply(1:K, function(k){rep(k, ns[k])})), ncol=1)) obs <- matrix(unlist(lapply(1:K, function(k){ rnorm(n=ns[k], mean=mus[k], sd=sigmas[k]) }))) new.order <- sample(1:N, N) obs <- obs[new.order] rownames(obs) <- NULL clusters <- clusters[new.order] return(list(obs=obs, clusters=clusters, mus=mus, sigmas=sigmas, mix.probas=ns/N)) }
#' Return probas of latent variables given data and parameters from previous iteration #' #' @param data Nx1 vector of observations #' @param params list which components are mus, sigmas and mix.probas Estep <- function(data, params){ GetMembershipProbas(data, params$mus, params$sigmas, params$mix.probas) } #' Return the membership probabilities P(zi=k/xi,theta) #' #' @param data Nx1 vector of observations #' @param mus Kx1 vector of means #' @param sigmas Kx1 vector of std deviations #' @param mix.probas Kx1 vector of mixing probas P(zi=k/theta) #' @return NxK matrix of membership probas GetMembershipProbas <- function(data, mus, sigmas, mix.probas){ N <- length(data) K <- length(mus) tmp <- matrix(unlist(lapply(1:N, function(i){ x <- data[i] norm.const <- sum(unlist(Map(function(mu, sigma, mix.proba){ mix.proba * GetUnivariateNormalDensity(x, mu, sigma)}, mus, sigmas, mix.probas))) unlist(Map(function(mu, sigma, mix.proba){ mix.proba * GetUnivariateNormalDensity(x, mu, sigma) / norm.const }, mus[-K], sigmas[-K], mix.probas[-K])) })), ncol=K-1, byrow=TRUE) membership.probas <- cbind(tmp, apply(tmp, 1, function(x){1 - sum(x)})) names(membership.probas) <- NULL return(membership.probas) } #' Univariate Normal density GetUnivariateNormalDensity <- function(x, mu, sigma){ return( 1/(sigma * sqrt(2*pi)) * exp(-1/(2*sigma^2)*(x-mu)^2) ) }
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