User:Stephanie Tietz/Notebook/Stephanies Notebook/2013/05/13: Difference between revisions
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*Determine the concentration and amounts needed for Au and BSA in a solution with 140 times more Au than BSA | *Determine the concentration and amounts needed for Au and BSA in a solution with 140 times more Au than BSA | ||
**Concentrations: | **Concentrations: | ||
Au = .25 mM | ***Au = .25 mM | ||
BSA = 1.785 μM | ***BSA = 1.785 μM | ||
**Amounts: | **Amounts: | ||
Au = .4924 mg | ***Au = .4924 mg | ||
BSA = 1.19 mg | ***BSA = 1.19 mg | ||
*Amounts needed multiplied by 10 to get 10 times the concentration in stock solutions | *Amounts needed multiplied by 10 to get 10 times the concentration in stock solutions | ||
**Theoretical Amounts: | **Theoretical Amounts: | ||
Au = 4.924 mg | ***Au = 4.924 mg | ||
BSA = 11.9 mg | ***BSA = 11.9 mg | ||
**Actual amounts used: | **Actual amounts used: | ||
Au = 5.3 mg | ***Au = 5.3 mg | ||
BSA = 12.6 mg | ***BSA = 12.6 mg | ||
**Adjusted mL based on extra amounts: | **Adjusted mL based on extra amounts: | ||
Au solution = 10.76mL | ***Au solution = 10.76mL | ||
BSA solution = 10.57mL | ***BSA solution = 10.57mL | ||
*1mL was siphoned from each solution and added to 8mL of purified water. | *1mL was siphoned from each solution and added to 8mL of purified water. | ||
Revision as of 08:22, 13 May 2013
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