User:Stephanie Tietz/Notebook/Stephanies Notebook/2013/05/13

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(Nanoparticle Fiber)
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==Nanoparticle Fiber==
==Nanoparticle Fiber==
*Determine the concentration and amounts needed for Au and BSA in a solution with 140 times more Au than BSA
*Determine the concentration and amounts needed for Au and BSA in a solution with 140 times more Au than BSA
-
Concentrations:
+
**Concentrations:
-
Au = .25 mM
+
Au = .25 mM,
BSA = 1.785 μM
BSA = 1.785 μM
-
Amounts:
+
**Amounts:
-
Au = .4924 mg
+
Au = .4924 mg,
BSA = 1.19 mg
BSA = 1.19 mg
*Amounts needed multiplied by 10 to get 10 times the concentration in stock solutions
*Amounts needed multiplied by 10 to get 10 times the concentration in stock solutions
-
Theoretical Amounts:
+
**Theoretical Amounts:
-
Au = 4.924 mg
+
Au = 4.924 mg,
BSA = 11.9 mg
BSA = 11.9 mg
-
Actual amounts used:
+
**Actual amounts used:
-
Au = 5.3 mg
+
Au = 5.3 mg,
BSA = 12.6 mg
BSA = 12.6 mg
-
Adjusted mL based on extra amounts:
+
**Adjusted mL based on extra amounts:
-
Au solution = 10.76mL
+
Au solution = 10.76mL,
BSA solution = 10.57mL
BSA solution = 10.57mL

Revision as of 10:20, 13 May 2013

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Nanoparticle Fiber

  • Determine the concentration and amounts needed for Au and BSA in a solution with 140 times more Au than BSA
    • Concentrations:

Au = .25 mM, BSA = 1.785 μM

    • Amounts:

Au = .4924 mg, BSA = 1.19 mg

  • Amounts needed multiplied by 10 to get 10 times the concentration in stock solutions
    • Theoretical Amounts:

Au = 4.924 mg, BSA = 11.9 mg

    • Actual amounts used:

Au = 5.3 mg, BSA = 12.6 mg

    • Adjusted mL based on extra amounts:

Au solution = 10.76mL, BSA solution = 10.57mL

  • 1mL was siphoned from each solution and added to 8mL of purified water.
  • The 10mL Au+BSA+H2O solution was then put into the oven for approximately 4 hours.



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