User:Stephanie Tietz/Notebook/Stephanies Notebook/2013/05/13

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==Entry title==
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==Nanoparticle Fiber==
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* Insert content here...
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* Determine the concentration and amounts needed for Au and BSA in a solution with 140 times more Au than BSA
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Concentrations:
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Au = .25 mM
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BSA = 1.785 μM
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Amounts:
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Au = .4924 mg
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BSA = 1.19 mg
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*Amounts needed multiplied by 10 to get 10 times the concentration, to later siphon out 1mL from each diluted solution
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Theoretical Amounts:
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Au = 4.924 mg
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BSA = 11.9 mg
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Actual amounts used:
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Au = 5.3 mg
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BSA = 12.6 mg
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Adjusted mL based on extra amounts:
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Au solution = 10.76mL
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BSA solution = 10.57mL
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*1mL was siphoned from each solution and added to 8mL of purified water.
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*The 10mL Au+BSA+H<sub>2</sub>O solution was then put into the oven for approximately 4 hours.

Revision as of 10:12, 13 May 2013

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Nanoparticle Fiber

  • Determine the concentration and amounts needed for Au and BSA in a solution with 140 times more Au than BSA

Concentrations: Au = .25 mM BSA = 1.785 μM

Amounts: Au = .4924 mg BSA = 1.19 mg

  • Amounts needed multiplied by 10 to get 10 times the concentration, to later siphon out 1mL from each diluted solution

Theoretical Amounts: Au = 4.924 mg BSA = 11.9 mg

Actual amounts used: Au = 5.3 mg BSA = 12.6 mg

Adjusted mL based on extra amounts: Au solution = 10.76mL BSA solution = 10.57mL

  • 1mL was siphoned from each solution and added to 8mL of purified water.
  • The 10mL Au+BSA+H2O solution was then put into the oven for approximately 4 hours.



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