User:Puja Mody/Notebook/Chem 571: Gold Nanoparticles/2012/09/25: Difference between revisions
From OpenWetWare
Line 24: | Line 24: | ||
*'''[[User:Abigail E. Miller|Abigail E. Miller]] 10:56, 7 October 2012 (EDT)''':be careful. this sounds more like what you will do, not what you actually did. having both in your notebook is fine, but having the first only is not. | *'''[[User:Abigail E. Miller|Abigail E. Miller]] 10:56, 7 October 2012 (EDT)''':be careful. this sounds more like what you will do, not what you actually did. having both in your notebook is fine, but having the first only is not. where are the details? did you use two different tubes for the flask 1 cells versus the other flasks? for example: the binding buffer ( 50 mM Tris, 100 mM NaCl and 50mM imidizole, pH 7.4)(create a link to the page it was made on) was filtered by vacuum filtration using filter paper with 450 nm pore size for 2 minutes. | ||
==DATA/Calculations== | ==DATA/Calculations== |
Revision as of 08:00, 7 October 2012
Project name | <html><img src="/images/9/94/Report.png" border="0" /></html> Main project page <html><img src="/images/c/c3/Resultset_previous.png" border="0" /></html>Previous entry<html> </html>Next entry<html><img src="/images/5/5c/Resultset_next.png" border="0" /></html> | |||||||||||||||||||||||||||
Separate ProteinsGoals
Procedure
DATA/Calculations
to make a 25mL stock solution of the tris buffer at a pH of 10 1mol/L x .025= .025 mol .025 mol x 121.14 g/mol = 3.0285 g of tris To get the necessary concentrations of tris into the gold/BSA solutions, the M1V1=M2V2 formula was used to calculate the volume of tris needed. From there, the value of the volume of tris was subtracted from 1 in order to determine the amount of water that would be added to make the desired concentration.
link for excel File:TrisvaryingmolarUVVis.xlsx Conclusions
|