User:Monika Gasiorek/Notebook/CHEM-571 2014F/2015/03/03: Difference between revisions
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=='''Pepsin Reaction Preparation'''== | =='''Pepsin Reaction Preparation'''== | ||
0.00166 g of pepsin was dissolved in 1 mL of | 0.00166 g of pepsin was dissolved in 1 mL of 5 mM citrate/0.2 M NaCl buffer ---> stock [pepsin] = 47.98 μM | ||
'''''Bradford/Gel Analysis samples''''' to be run: | |||
1. 0.104(2) mL of stock solution in 4.896 mL of citrate/NaCl buffer | |||
*[pepsin]<sub>final</sub> = 1 μM | |||
2. 0.010(4) mL of stock solution in 4.989 mL of citrate/NaCl buffer | |||
*[pepsin]<sub>final</sub> = 100 nM | |||
3. 0.001(0) mL of stock solution in 4.999 mL of citrate/NaCl buffer | |||
*[pepsin]<sub>final</sub> = 10 nM | |||
4. 10 μL of stock solution in 990 μL of Tris/NaCl buffer --> [trypsin] = 0.4798 μM | |||
**Take 0.010(4) mL of dilution in 4.989 mL of Tris/NaCl buffer | |||
*[pepsin]<sub>final</sub> = 1 nM | |||
=='''Thermolysin Reaction Preparation'''== | =='''Thermolysin Reaction Preparation'''== |
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Entry titlePepsin Reaction Preparation0.00166 g of pepsin was dissolved in 1 mL of 5 mM citrate/0.2 M NaCl buffer ---> stock [pepsin] = 47.98 μM Bradford/Gel Analysis samples to be run: 1. 0.104(2) mL of stock solution in 4.896 mL of citrate/NaCl buffer
2. 0.010(4) mL of stock solution in 4.989 mL of citrate/NaCl buffer
3. 0.001(0) mL of stock solution in 4.999 mL of citrate/NaCl buffer
4. 10 μL of stock solution in 990 μL of Tris/NaCl buffer --> [trypsin] = 0.4798 μM
Thermolysin Reaction Preparation0.00063 g of Chymotrypsin was dissolved in 1 mL of Tris/NaCl buffer ---> stock [thermolysin] =
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