User:Monika Gasiorek/Notebook/CHEM-571 2014F/2015/03/03: Difference between revisions

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=='''Pepsin Reaction Preparation'''==
=='''Pepsin Reaction Preparation'''==


0.00166 g of pepsin was dissolved in 1 mL of Tris/NaCl buffer ---> stock [pepsin] =  
0.00166 g of pepsin was dissolved in 1 mL of 5 mM citrate/0.2 M NaCl buffer ---> stock [pepsin] = 47.98 μM
 
'''''Bradford/Gel Analysis samples''''' to be run:
 
1. 0.104(2) mL of stock solution in 4.896 mL of citrate/NaCl buffer
*[pepsin]<sub>final</sub> = 1 μM
 
2. 0.010(4) mL of stock solution in 4.989 mL of citrate/NaCl buffer
*[pepsin]<sub>final</sub> = 100 nM
 
3. 0.001(0) mL of stock solution in 4.999 mL of citrate/NaCl buffer
*[pepsin]<sub>final</sub> = 10 nM
 
4. 10 μL of stock solution in 990 μL of Tris/NaCl buffer --> [trypsin] = 0.4798 μM
**Take 0.010(4) mL of dilution in 4.989 mL of Tris/NaCl buffer
*[pepsin]<sub>final</sub> = 1 nM


=='''Thermolysin Reaction Preparation'''==
=='''Thermolysin Reaction Preparation'''==

Revision as of 13:42, 1 March 2015

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Pepsin Reaction Preparation

0.00166 g of pepsin was dissolved in 1 mL of 5 mM citrate/0.2 M NaCl buffer ---> stock [pepsin] = 47.98 μM

Bradford/Gel Analysis samples to be run:

1. 0.104(2) mL of stock solution in 4.896 mL of citrate/NaCl buffer

  • [pepsin]final = 1 μM

2. 0.010(4) mL of stock solution in 4.989 mL of citrate/NaCl buffer

  • [pepsin]final = 100 nM

3. 0.001(0) mL of stock solution in 4.999 mL of citrate/NaCl buffer

  • [pepsin]final = 10 nM

4. 10 μL of stock solution in 990 μL of Tris/NaCl buffer --> [trypsin] = 0.4798 μM

    • Take 0.010(4) mL of dilution in 4.989 mL of Tris/NaCl buffer
  • [pepsin]final = 1 nM

Thermolysin Reaction Preparation

0.00063 g of Chymotrypsin was dissolved in 1 mL of Tris/NaCl buffer ---> stock [thermolysin] =