User:Moira M. Esson/Notebook/CHEM-581/2012/11/09

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(Calculations)
(Objectives)
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==Objectives==
==Objectives==
#Prepare solutions to run new PVOH based reactions
#Prepare solutions to run new PVOH based reactions
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*First PVOH reaction will be the synthesis of polyvinyl acetate
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*Second PVOH reaction will be the attachment of 5-(4,6-Dichlorotriazinyl)Aminofluorescein which will be referred to as 5-DTAF
 +
#Perform all calculations necessary for future PVOH reactions
 +
==General Formula for reactions==
==General Formula for reactions==

Revision as of 16:39, 26 November 2012

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Objectives

  1. Prepare solutions to run new PVOH based reactions
  • First PVOH reaction will be the synthesis of polyvinyl acetate
  • Second PVOH reaction will be the attachment of 5-(4,6-Dichlorotriazinyl)Aminofluorescein which will be referred to as 5-DTAF
  1. Perform all calculations necessary for future PVOH reactions

General Formula for reactions

Polyvinyl alcohol + [HAc]→Polyvinyl acetate

General Protocol for Polyvinyl acetate synthesis

  1. For a 1:1 ratio of polyvinyl alcohol OH groups to polyvinyl acetate dissolve ~1g PVOH inH2O
  2. Add ~1.36g HAc. Add ~2 drops of HCl to reaction mixture to catalyze reaction.
  3. Heat the reaction mixture to 40°C.
  4. Allow the reaction to stir for 1 hour
  5. Add sodium bicarbonate solution to the reaction mixture(titrate the reaction)
  6. Rotavap the remaining reaction mixture


Calculations

  • Overall, want to determine if have 1g of material how many moles of -OH groups. Once that is determined, will want to determine how many moles of -OH was reacted after the reaction.

Number of moles of OH groups in 1g PVOH: MW of repeating polyvinyl alcohol unit [C2H3OH]: 44.06g/mol

Polyvinyl alcohol repeating unit picture

 1gPVOH(1mol PVOH unit/44.06g) x (1mol OH/1mol PVOH unit)= 0.022696 mol OH/g 

Dye attachment calculations:

  • Want to react .01% of the OH groups with the dye

MW 5-DTAF dye: 495.28g/mol

 (0.0227mol OH/g) x (.0001)= 2.27x10-6 moles dye


  2.27x10-6 moles dye x(495.28g dye/1mol dye)=0.001124g dye


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