User:Moira M. Esson/Notebook/CHEM-581/2012/11/09: Difference between revisions

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==Calculations==
==Calculations==
*Overall, want to determine if have 1g of material how many moles of -OH groups. Once that is determined, will want to determine how many moles of -OH was reacted after the reaction.


'''Number of moles of OH groups in 1g PVOH''':
MW of repeating polyvinyl alcohol unit [C<sub>2</sub>H<sub>3</sub>OH]: 44.06g/mol
[http://www.britannica.com/EBchecked/topic/469236/polyvinyl-alcohol-PVA Polyvinyl alcohol repeating unit picture]
  1gPVOH(1mol PVOH unit/44.06g) x (1mol OH/1mol PVOH unit)= 0.022696 mol OH/g
'''Dye attachment calculations''':
*Want to react .01% of the OH groups with the dye
MW 5-DTAF dye: 495.28g/mol
<br>
  (0.0227mol OH/g) x (.0001)= 2.27x10<sup>-6</sup> moles dye
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  2.27x10<sup>-6</sup> moles dye x(495.28g dye/1mol dye)=0.001124g dye


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Revision as of 13:37, 26 November 2012

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Objectives

  1. Prepare solutions to run new PVOH based reactions

General Formula for reactions

Polyvinyl alcohol + [HAc]→Polyvinyl acetate

General Protocol for Polyvinyl acetate synthesis

  1. For a 1:1 ratio of polyvinyl alcohol OH groups to polyvinyl acetate dissolve ~1g PVOH inH2O
  2. Add ~1.36g HAc. Add ~2 drops of HCl to reaction mixture to catalyze reaction.
  3. Heat the reaction mixture to 40°C.
  4. Allow the reaction to stir for 1 hour
  5. Add sodium bicarbonate solution to the reaction mixture(titrate the reaction)
  6. Rotavap the remaining reaction mixture


Calculations

  • Overall, want to determine if have 1g of material how many moles of -OH groups. Once that is determined, will want to determine how many moles of -OH was reacted after the reaction.

Number of moles of OH groups in 1g PVOH: MW of repeating polyvinyl alcohol unit [C2H3OH]: 44.06g/mol

Polyvinyl alcohol repeating unit picture 

 1gPVOH(1mol PVOH unit/44.06g) x (1mol OH/1mol PVOH unit)= 0.022696 mol OH/g

Dye attachment calculations:

  • Want to react .01% of the OH groups with the dye

MW 5-DTAF dye: 495.28g/mol 

 (0.0227mol OH/g) x (.0001)= 2.27x10-6 moles dye



  2.27x10-6 moles dye x(495.28g dye/1mol dye)=0.001124g dye


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