User:Mobeen Ashraf/Notebook/Chem-581/2012/10/31: Difference between revisions
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==Description== | ==Description== | ||
* | *6 molal NaCl solution was prepared. Porphyrin was submerged in the solution for an hour at 70 degrees Celsius under constant stirring. | ||
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* 6 m NaCl solution was prepared in a following manner: | |||
(6 mol/1Kg H2O) * (57.54 g NaCl/mol NaCl) = 345.24 g NaCl/1 Kg of H2O. 1 Kg of water is equivalent to 1,000 mL of H2O. Therefore, 6 m NaCl solution should be equivalent to 34.5 g NaCl/100 mL H2O. | |||
==Data== | ==Data== |
Revision as of 12:04, 28 November 2012
Experimental Chemistry | <html><img src="/images/9/94/Report.png" border="0" /></html> Main project page <html><img src="/images/c/c3/Resultset_previous.png" border="0" /></html>Previous entry<html> </html>Next entry<html><img src="/images/5/5c/Resultset_next.png" border="0" /></html> |
ObjectiveCatalysis and Stimulation of Cross-Linking Studies. Description
(6 mol/1Kg H2O) * (57.54 g NaCl/mol NaCl) = 345.24 g NaCl/1 Kg of H2O. 1 Kg of water is equivalent to 1,000 mL of H2O. Therefore, 6 m NaCl solution should be equivalent to 34.5 g NaCl/100 mL H2O. Data
NotesThis area is for any observations or conclusions that you would like to note.
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