User:Michael S. Bible/Notebook/581/2014/09/12: Difference between revisions
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As before we needed to make a 10% clay film, so we used 1g of PVA and 2.5387g of exfoliated clay solution. The calculations that led to these numbers can be found below. | As before we needed to make a 10% clay film, so we used 1g of PVA and 2.5387g of exfoliated clay solution. The calculations that led to these numbers can be found below. | ||
== | ==Calculations== | ||
A 10% clay has 1g of PVA and should have .11g of exfoliated clay. | |||
.11g of clay = (4% solution)x = (0.04)x | |||
x = 2.75g of exfoliated clay solution | |||
Actual mass of solution used was 2.5387g. | |||
==Data== | ==Data== | ||
Revision as of 09:58, 12 September 2014
 Biomaterials Design Lab
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Preparation of New Films using Exfoliated ClayToday we created a film using a exfoliated clay rather than plain sodium montmorillonite. The exfoliated clay has had all of its layers separated from one another. So, instead of having layers in water as before, we now have single sheets of material. Theoretically, this should impact the clay's absorption properties. Dr. Fox prepared exfoliated clay solution for us that was 4% sodium montmorillonite. As before we needed to make a 10% clay film, so we used 1g of PVA and 2.5387g of exfoliated clay solution. The calculations that led to these numbers can be found below. CalculationsA 10% clay has 1g of PVA and should have .11g of exfoliated clay. .11g of clay = (4% solution)x = (0.04)x x = 2.75g of exfoliated clay solution Actual mass of solution used was 2.5387g. Data
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