# User:Melissa Novy/Notebook/CHEM-572/2013/03/27

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 Revision as of 12:53, 2 April 2013 (view source) (Autocreate 2013/03/27 Entry for User:Melissa_Novy/Notebook/CHEM-572)← Previous diff Current revision (13:03, 2 April 2013) (view source) (→Objectives) (One intermediate revision not shown.) Line 15: Line 15: - ==Entry title== + ==Objectives== - * Insert content here... + * Calculate the amount of silver-loaded clay necessary to achieve theoretical leaching of 2.5 μmol Ag+ in 50 mL of solution. + * Make 3 g film of PLA2002D + 33wt% LMT. + + ==Calculations== + '''MW Ag+: 107.87 g/mol''' + '''MW AgNO3: 169.87 g/mol''' + '''Given that 3.662 μmol Ag+ was exchanged into 1.49711 g LMT, (3.662 μmol Ag+)/(1.49711 g LMT) = (2.5 μmol Ag+)/(x g LMT)''' + '''x = 1.02206 g LMT''' +
+ + * Therefore, 2.5 μmol Ag+ is present in 1.02206 g of 100AgLMT.  The corresponding control film must be 3 g PLA2002D with 1.02206 g LMT. + + ==Film of PLA2002D + 33wt% LMT== + * Actual mass PLA2002D: 3.03753 g + * Actual mass LMT: 1.02205 g

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## Objectives

• Calculate the amount of silver-loaded clay necessary to achieve theoretical leaching of 2.5 μmol Ag+ in 50 mL of solution.
• Make 3 g film of PLA2002D + 33wt% LMT.

## Calculations

```  MW Ag+: 107.87 g/mol
MW AgNO3: 169.87 g/mol
Given that 3.662 μmol Ag+ was exchanged into 1.49711 g LMT, (3.662 μmol Ag+)/(1.49711 g LMT) = (2.5 μmol Ag+)/(x g LMT)
x = 1.02206 g LMT
```

• Therefore, 2.5 μmol Ag+ is present in 1.02206 g of 100AgLMT. The corresponding control film must be 3 g PLA2002D with 1.02206 g LMT.

## Film of PLA2002D + 33wt% LMT

• Actual mass PLA2002D: 3.03753 g
• Actual mass LMT: 1.02205 g