User:Melissa Novy/Notebook/CHEM-572/2013/02/20
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| align="center" style="background:#f0f0f0;"|'''Time [min]''' | | align="center" style="background:#f0f0f0;"|'''Time [min]''' | ||
| align="center" style="background:#f0f0f0;"|'''Conductivity [mV]''' | | align="center" style="background:#f0f0f0;"|'''Conductivity [mV]''' | ||
| + | | align="center" style="background:#f0f0f0;"|'''[Ag+] [M]''' | ||
| + | | align="center" style="background:#f0f0f0;"|'''mol Ag+ [umol]''' | ||
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| - | | 0||384.9 | + | | 0||384.9||0.000204407||10.42474353 |
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| - | | 30||379.9 | + | | 30||379.9||0.000163526||8.339821664 |
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| - | | 60||372.5 | + | | 60||372.5||0.000117534||5.994210823 |
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| - | | 90||367.2 | + | | 90||367.2||9.27767E-05||4.731609351 |
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| - | | 120||366.8 | + | | 120||366.8||9.11352E-05||4.647893756 |
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Revision as of 21:28, 27 February 2013
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Objectives
DH5α-T1 Cell Harvesting
X-Ray Diffraction on 100Ag-LMT
Calculations
1 μM Ag+ in 50 mL of LB media (0.0105 M Ag+) × V1 = (1×10-6 M) × (50 mL) V1 = 0.00476 mL of 0.0105 M AgNO3 10 μM Ag+ in 50 mL of LB media (0.1 M Ag+) × V1 = (10×10-6 M) × (50 mL) V1 = 0.005 mL of 0.1 M AgNO3
ISE Study of PLA2002D + 5 wt% 100Ag-LMT
(4.47 × 10-8mol Ag+0 ÷ 0.051 L = 8.76 × 10-7 M or 0.876 μM
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