User:Mary Mendoza/Notebook/CHEM 571 Experimental Biological Chemistry I/2012/11/13
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ADA Kinetic Assay Preparations
.050 L of water × [math]\displaystyle{ \frac{0.05 mol}{1L} }[/math] = .0025 mol of Na2HPO4 × [math]\displaystyle{ \frac{268.07 g}{1 mol} }[/math] = 0.6702 g
.0015 g of inosine × [math]\displaystyle{ \frac{1 mol}{268.2 g} }[/math] = .000005596 mol ÷ .001 L = .005596 M = 5.596 mM 5.596 mM (V1)= 0.1 mM (5 mL) V1 = 0.08934 mL = 89.3 μL in 5 mL of buffer
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