User:Mary Mendoza/Notebook/CHEM 571 Experimental Biological Chemistry I/2012/11/13
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M<sub>2</sub> = .0975 μM = 97.5 nM | M<sub>2</sub> = .0975 μM = 97.5 nM | ||
| + | * 2 additional 500 μL dilutions of 97.5 nM to 1000 μL were executed using the dilution equation. | ||
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| + | Second dilution M = 48.8 nM | ||
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| + | Final Concentration = 24.38 nM | ||
Revision as of 11:15, 9 December 2012
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ADA Kinetic Assay Preparations
V1 = 0.08934 mL = 89.3 μL in 5 mL of buffer
UV-visible scans of Reagents
M1V1 = M2V2 (3 mM)(10 μL) = M2 (1000 μL) M2 = .0307 mM
3 μL of ADA × 65 μM = M2 (1000 μL) M2 = .195 μM of ADA
M2 = .0975 μM = 97.5 nM
Second dilution M = 48.8 nM Final Concentration = 24.38 nM
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= .0025 mol of Na2HPO4 ×
= 0.6702 g
= .000005596 mol ÷ .001 L = .005596 M = 5.596 mM
= 3.06840 × 10-5 ÷ .010 L = .00307 M = 3.07 mM


