User:Mary Mendoza/Notebook/CHEM 571 Experimental Biological Chemistry I/2012/10/02
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| - | x<sub>60 mL</sub> = | + | x<sub>60 mL</sub> = <math>\frac{.060 L of H_2_O * 53. 61 g}{1L}</math> |
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Revision as of 22:32, 6 October 2012
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Preparation of the Reactants of HRP Oxidase Assay
0.020 mol of Na2HPO4 ×
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of Na2HPO4 = 53.61 g of Na2HPO4


