User:Mary Mendoza/Notebook/CHEM 571 Experimental Biological Chemistry I/2012/08/29: Difference between revisions
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* The amount of .085 g was acquired from the following calculation: | * The amount of .085 g was acquired from the following calculation: | ||
.025 L × (10×10<sup>-3</sup> mM ÷ 1L)= .00025 mM | .025 L × (10×10<sup>-3</sup> mM ÷ 1L)= .00025 mM × 339. 79 g (formula weight of HAuCl<sub>4</sub>)= .085 g | ||
Revision as of 12:12, 14 September 2012
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Preparation of Gold and Bovine Serum Albumin Stock Solutions
.025 L × (10×10-3 mM ÷ 1L)= .00025 mM × 339. 79 g (formula weight of HAuCl4)= .085 g
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