User:Mary Mendoza/Notebook/CHEM572 Exp. Biological Chemistry II/2013/01/23
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* It was decided to prepare a 30 mM stock solution of adenosine. The calculation below shows the amount needed to obtain 30 mM of adenosine. | * It was decided to prepare a 30 mM stock solution of adenosine. The calculation below shows the amount needed to obtain 30 mM of adenosine. | ||
| - | <math> | + | .030 <math>\frac{mol}{L}</math> mol of adenosine × <math>\frac{267.24 g}{1 mol}</math> = <math>\frac{8.0172 g}{L}</math> × .010 L = 0.0802 g of adenosine |
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| + | The calculations on the bottom are courtesy of [[User:Dhea Patel/Notebook/CHEM 572: ADA&Inhibitor Kinetics/2013/01/23|Dhea Patel]]. | ||
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| + | [[Image:ADA_kinetics_table.png|px80]] | ||
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| + | The calculation of for the buffer was formulated by [[User:Catherine Koenigsknecht/Notebook/Experimental Biological Chemistry/2013/01/23|Catherine Koenigsknecht]]. | ||
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| + | * Procedure: Buffer | ||
| + | #Protocol for 0.1 M Sodium Phosphate Buffer (pH 7.4) | ||
| + | #Add 3.1 g of NaH2PO4•H2O and 10.9 g of Na2HPO4 (anhydrous) to distilled H2O to make a volume of 1 L. The pH of the final solution will be 7.4. This buffer can be stored for up to 1 mo at 4°C. | ||
| + | #Dilute to 0.05M: (take 50 mL of 1M solution and dilute in 1 Liter H2O) | ||
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Revision as of 16:34, 23 January 2013
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Calculation of reagents for ADA kinetic assay
.030
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mol of adenosine ×
=
× .010 L = 0.0802 g of adenosine



