User:Mary Mendoza/Notebook/CHEM572 Exp. Biological Chemistry II/2013/01/23

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Revision as of 16:31, 23 January 2013

Project name

It was decided to prepare a 30 mM stock solution of adenosine. The calculation below shows the amount needed to obtain 30 mM of adenosine.

.030 $\frac{mol}{L}$ mol of adenosine × $\frac{267.24 g}{1 mol}$ = $\frac{8.0172 g}{L}$ × .010 L = 0.0802 g of adenosine

The calculations on the bottom are courtesy of Dhea Patel.

The calculation of for the buffer was formulated by Catherine Koenigsknecht

Protocol for 0.1 M Sodium Phosphate Buffer (pH 7.4)
Add 3.1 g of NaH2PO4•H2O and 10.9 g of Na2HPO4 (anhydrous) to distilled H2O to make a volume of 1 L. The pH of the final solution will be 7.4. This buffer can be stored for up to 1 mo at 4°C.
Dilute to 0.05M: (take 50 mL of 1M solution and dilute in 1 Liter H2O)

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 .030  <math>\frac{mol}{L}</math> mol of adenosine × <math>\frac{267.24  g}{1  mol}</math> = <math>\frac{8.0172 g}{L}</math> × .010 L = 0.0802 g of adenosine
+The calculations on the bottom are courtesy of Dhea Patel.
 [[Image:ADA_kinetics_table.png|px80]]
+The calculation of for the buffer was formulated by [[User:Catherine Koenigsknecht/Notebook/Experimental Biological Chemistry/2013/01/23|Catherine Koenigsknecht]]
+* Procedure: Buffer
+#Protocol for 0.1 M Sodium Phosphate Buffer (pH 7.4)
+#Add 3.1 g of NaH2PO4•H2O and 10.9 g of Na2HPO4 (anhydrous) to distilled H2O to make a volume of 1 L. The pH of the final solution will be 7.4. This buffer can be stored for up to 1 mo at 4°C.
+#Dilute to 0.05M: (take 50 mL of 1M solution and dilute in 1 Liter H2O)
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